sin(-1),是多少，题目上说6/兀<-1<4/兀，看不懂
sin\uff08\u5140/6\u4e00a\uff09=1/4\uff0c\u5219sin\uff08\u5140/6+2a\uff09=________sin(\u03c0/6+2a)=cos(\u03c0/2-\u03c0/6-2a)
=cos(\u03c0/3-2a)
=1-2sin²(\u03c0/6-a)
=1-2\u00d7(1/4)²
=7/8
sin(\u03c0\uff0d\u03c0/6)=sin5\u03c0/6\u56e0\u4e3a\u4e00\u4e8c\u8c61\u9650sin\u90fd\u662f\u6b63\u6570\u3002\u6240\u4ee5sin5\u03c0/6\u5c31\u7b49\u4e8esin\u03c0/6
意思应该是-4/兀<sin(-1)<-6/兀绛旓細鎰忔濆簲璇ユ槸-4/鍏<sin(-1)<-6/鍏
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