化学：在标准状况下，将224L HCl气体溶于635mL水中，所得盐酸的密度为1.18g/cm3，取此盐酸10ML， 在标准状况下, 将224LHCl气体溶于635mL水中, 所...
\u5728\u6807\u51c6\u72b6\u51b5\u4e0b\uff0c\u5c06224LHCl\u6c14\u4f53\u6eb6\u4e8e635mL\u6c34\u4e2d\uff0c\u6240\u5f97\u76d0\u9178\u7684\u5bc6\u5ea6\u4e3a1.18g/cm3\uff0e\u8bd5\u8ba1\u7b97\uff1a\uff081\uff09\u53d6\u51fa\u8fd9\u79cd\u76d0\u9178100m\uff081\uff09n\uff08HCl\uff09=224L22.4L/mol=10mol\uff0cm\uff08HCl\uff09=10mol\u00d736.5g?mol-1=365g\uff0c\u6eb6\u6db2\u7684\u4f53\u79efV=365g+635g1.18g/cm3=847ml=0.847L\uff0c\u7a00\u76d0\u9178\u7684\u7269\u8d28\u7684\u91cf\u6d53\u5ea6c=10mol0.847L=11.8mol/L\uff1b\u8bbe\u7a00\u91ca\u540e\u5f97\u76d0\u9178\u7684\u6d53\u5ea6\u4e3ac1\uff0c\u7531\u7a00\u91ca\u5b9a\u5f8b\u53ef\u5f97\uff1a11.8mol/L\u00d70.1L=c1\u00d71.18L\uff0c\u89e3\u5f97\uff1ac1=1mol/L\uff0c\u6545\u7b54\u6848\u4e3a1mol/L\uff1a\uff082\uff09n\uff08Na2CO3\uff09=0.040L\u00d70.065mol?L-1=0.0026 mol\uff0c\u8bbe\u52a0\u5165\u7a00\u76d0\u9178\u7684\u4f53\u79ef\u6700\u591a\u4e0d\u8d85\u8fc7x mL\uff0c\u5219n\uff08HCl\uff09=1mol?L-1\u00d70.001x L=0.001x mol\uff0c\u6839\u636e\u53cd\u5e94Na2CO3+HCl\u2550NaHCO3+NaCl\uff0c\u53ef\u5f970.0026=0.001x\uff0c\u89e3\u5f97x=2.6\uff0c\u6545\u7b54\u6848\u4e3a\uff1a2.6\uff1b\uff083\uff09\u7ecf\u8fc7\u53cd\u5e94\uff0c\u84b8\u53d1\u4e2d\u548c\u540e\u7684\u6eb6\u6db2\uff0c\u6700\u540e\u6240\u5f97\u56fa\u4f53\u4e3aNaCl\uff0c\u6839\u636eCl\u5143\u7d20\u5b88\u6052\uff1an\uff08NaCl\uff09=n\uff08HCl\uff09=0.050L\u00d72mol?L-1=0.1mol\uff0c\u6545m\uff08NaCl\uff09=0.1mol\u00d758.5g?mol-1=5.85g\uff0c\u6545\u7b54\u6848\u4e3a\uff1a5.85\uff0e
\u78b3\u9178\u94a0\u4e0e\u6c2f\u5316\u6c22\u53cd\u5e94\u751f\u6210\u78b3\u9178\u6c22\u94a0\u7684\u53cd\u5e94\u65b9\u7a0b\u5f0f\u662f\uff1a
Na2CO3
+
HCl
\u2192
NaHCO3
+
NaCl
\u6469\u5c14\u6bd4\uff1a1\u2026\u2026\u2026\u20261\u2026\u2026\u2026\u20261
\u78b3\u9178\u94a0\u6eb6\u6db2\u4e2d\u542b\u6709\u7684\u6eb6\u8d28\u6469\u5c14\u6570\u4e3a\uff1a
(0.065mol/1000ml)*40ml=0.0026mol
\u628a\u78b3\u9178\u94a0\u4e2d\u548c\u6210\u78b3\u9178\u6c22\u94a0\u6240\u9700\u7684\u7a00\u76d0\u9178\u4f53\u79efV\u662f\uff1a
V*0.08mol/1000ml=0.0026mol
V=0.0026mol/(0.08mol/1000ml)
=32.5ml
\uff08\u6700\u591a\u4e0d\u80fd\u8d85\u8fc7\u7684\u4f53\u79ef\uff09\u3002
\u9898\u76ee\u201c\u5728\u6807\u51c6\u72b6\u51b5\u4e0b\uff0c\u5c06224LHCl\u6c14\u4f53\u6eb6\u4e8e635ml\u6c34\uff0c\u6240\u5f97\u7a00\u76d0\u9178\u6d53\u5ea6\u4e3a1.18g/cm³\u201d\u8fd9\u6bb5\u5185\u5bb9\u6ca1\u6709\u7528\u5904\u3002
∴m（HCl）=n（HCl）·M（HCl）=10·36.5=365g，m（H20）=635g（水的密度是1g/cm3）
∴盐配质量m为m（HCl）+m（H20）=1000g，其中HCl的质量分数为36.5%。
而10mL盐酸的质量为1.18×10=11.8g，其中含HCl11.8g×36.5%=4.307g。
则此时n（HCl）=m（HCl）/M（HCl）=4.307g÷36.5g/mol=0.118mol
所以在1.45L的溶液中，量浓度为
c=n/V=0.118mol/1.45L=0.08mol/L。
即它的量浓度约为0.08mol/L
......
224L=10mol
635ml取10ml=10mol取10*(10/635)mol HCl
c=n/v约等于0.1086mol/L
这样可以不....
绛旓細瑙ｏ細锛1锛224L鐨勬隘鍖栨阿姘斾綋鐨勭墿璐ㄧ殑閲忎负锛歯(HCl) = V / Vm = 224 / 22.4 = 10mol 鍒欙紝姘寲姘㈢殑璐ㄩ噺涓猴細m(HCl) = n * M = 10 * 36.5 = 365g 閰嶅埗鎴愮殑姘寲姘㈡憾娑茬殑鎬昏川閲忔槸锛歮(婧舵恫) = m(HCl) + m(姘) = 365 + 635*1 = 1000g 鎵浠ワ紝鐩愰吀鐨勮川閲忓垎鏁版槸锛歸(HCl) =...
绛旓細锛1锛224L姘寲姘㈡皵浣撶墿璐ㄧ殑閲忎负224L22.4L/mol=10mol锛岀瓟锛氭墍寰楃洂閰镐腑婧惰川鐗╄川鐨勯噺鏄10mol锛涳紙1锛夋晠HCl鐨勮川閲=10mL脳36.5g/mol=365g锛屾按鐨勮川閲忎负635mL脳1g/mL=635g锛岃婧舵恫璐ㄩ噺鍒嗘暟涓365g365g+635g脳100%=36.5%锛岀瓟锛氳鐩愰吀涓憾璐ㄧ殑璐ㄩ噺鍒嗘暟鏄36.5%锛涳紙3锛夎鐩愰吀鐨勭墿璐ㄧ殑閲忔祿搴︿负1000...
绛旓細锛1锛224L姘寲姘㈡皵浣撶墿璐ㄧ殑閲忎负224L22.4L/mol=10mol锛屾晠HCl鐨勮川閲=10mL脳36.5g/mol=365g锛屾按鐨勮川閲忎负635mL脳1g/mL=635g锛岃婧舵恫璐ㄩ噺鍒嗘暟涓365g365g+635g脳100%=36.5%锛岀瓟锛氳鐩愰吀涓憾璐ㄧ殑璐ㄩ噺鍒嗘暟鏄36.5%锛涳紙2锛夎鐩愰吀鐨勭墿璐ㄧ殑閲忔祿搴︿负1000脳1.18脳36.5%36.5mol/L=11.8mol/L锛屼护...
绛旓細瑙ｏ細鐢变簬婧舵恫鐨勮川閲忕瓑浜庢憾璐ㄥ姞婧跺墏锛岃宧cl鏈224/22.4=10mol锛屸埓m锛坔cl锛=n锛坔cl锛壜穖锛坔cl锛=10路36.5=365g锛宮锛坔20锛=635g锛堟按鐨勫瘑搴︽槸1g/cm3锛夆埓鐩愰厤璐ㄩ噺m涓簃锛坔cl锛+m锛坔20锛=1000g锛屽叾涓環cl鐨勮川閲忓垎鏁颁负36.5%銆傝10ml鐩愰吀鐨勮川閲忎负1.18脳10=11.8g锛屽叾涓惈hcl11.8g脳36.5%=4.3...
绛旓細婧惰川姘寲姘㈢殑鎽╁皵鏁版槸锛224L/(22.4L/mol=10.0mol 锛涙隘鍖栨阿婧朵簬姘村悗寰楀埌鐨勬憾娑茶川閲忔槸锛10.0mol*36.5g/mol+635ml*1.00g/ml =365g+635g=1000g 锛涙隘鍖栨阿姘存憾娑茬殑浣撶Н鏄細1000g/(1.18g/ml)=847ml 锛涙墍寰楃洂閰哥殑鐗╄川閲忔祿搴︽槸锛(10.0mol/847ml)*1000ml/L=11.8mol/L 銆
绛旓細mol-1=365g锛屾憾娑茬殑浣撶НV=365g+635g1.18g/cm3=847ml=0.847L锛绋鐩愰吀鐨勭墿璐ㄧ殑閲忔祿搴=10mol0.847L=11.8mol/L锛涜绋閲婂悗寰楃洂閰哥殑娴撳害涓篶1锛岀敱绋閲婂畾寰嬪彲寰楋細11.8mol/L脳0.1L=c1脳1.18L锛岃В寰楋細c1=1mol/L锛屾晠绛旀涓1mol/L锛锛2锛塶锛圢a2CO3锛=0.040L脳0.065mol?L-1=0.0026 ...
绛旓細銆愮瓟妗堛戯紙1锛夆憼11.8mol/L 鈶1mol/L 鍋忓ぇ 鈶2.6 锛2锛夆憼16.0 绛変簬 澶т簬 鈶″皬浜 灏忎簬 銆愮瓟妗堣В鏋愩戣瘯棰樺垎鏋愶細锛1锛夆憼鏍囧噯鐘跺喌涓嬶紝灏224 L HCl姘斾綋婧朵簬635 mL姘翠腑锛孒Cl鐨勭墿璐ㄧ殑鏄224L/22.4L/mol=10mol锛岃川閲忔槸10mol脳36.5g/mol=365g锛屾按鐨勮川閲忔槸635g锛屾墍寰楃洂閰哥殑璐ㄩ噺鏄365+...
绛旓細锛1锛224LHCl鐨勭墿璐ㄧ殑閲忎负 224L 22.4L/mol =10mol锛孒Cl鐨勮川閲忎负10mol脳36.5g/mol=365g锛635mL姘寸殑璐ㄩ噺涓635mL脳1g/mL=635g锛屾晠婧舵恫鐨勮川閲忎负锛635g+365g=1000g锛屾晠鎵寰楃洂閰哥殑浣撶Н= 1000g 1200g/L = 5 6 L锛屾墍寰楃洂閰哥殑鐗╄川鐨勯噺娴撳害涓猴細c= 10mol ...
绛旓細锛1锛塶锛圚Cl锛=224L22.4L/mol=10mol锛宮锛圚Cl锛=10mol脳36.5g?mol-1=365g锛635mL姘寸殑璐ㄩ噺涓635mL脳1g/mL=635g锛岀洂閰哥殑璐ㄩ噺鍒嗘暟w=365g365g+635g脳100%=36.5%锛宑锛圚Cl锛=1000蟻蠅M=1000脳1.18脳36.5%36.5mol/L=11.8mol/L锛岀瓟锛氭墍寰楃洂閰哥殑鐗╄川鐨勯噺娴撳害涓11.8mol/L锛涳紙2锛...
绛旓細n=224/22.4=10mol 婧舵恫浣撶Н涓篤 V=m梅瀵嗗害 m=婧惰川+婧跺墏=10*36.5+635*1.0=1000g c=n/V=10梅[锛1000梅1.18锛*10^-3]=11.8mol/L 鐢ㄥ瘑搴︾畻鍑烘潵鐨勪綋绉崟浣嶆槸ml 鎹㈢畻鎴怢 鎵浠ヤ箻浠10^-3
