解方程不等式? 解不等式方程

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x²-3x+2<0

∴(x-1)(x-2)<0

∴1<X<2

∴解集为﹛X│1<X<2﹜

通常不等式中的数是实数,字母也代表实数,不等式的一般形式为F(x,y,……,z)≤G(x,y,……,z )(其中不等号也可以为<,≥,> 中某一个),两边的解析式的公共定义域称为不等式的定义域,不等式既可以表达一个命题,也可以表示一个问题。

①如果x>y,那么y<x;如果y<x,那么x>y;

②如果x>y,y>z;那么x>z;

③如果x>y,而z为任意实数或整式,那么x+z>y+z;

④ 如果x>y,z>0,那么xz>yz;如果x>y,z<0,那么xz<yz;

⑤如果x>y,z>0,那么x÷z>y÷z;如果x>y,z<0,那么x÷z<y÷z。

扩展资料:

解不等式组步骤:

1.分别将不等式组中的各不等式设上①②③....

2.分别解出不等式

格式为:解①得....解②得...

3.可以在数轴上分别表示出来。

4.将原来的解联立起来形成解集。

5.若无解,则写上:此不等式组无解。

如果不等式F(x)<G(x) 的定义域被解析式H(x)的定义域所包含,并且H(x)>0,那么不等式F(x)<G(x)与不等式H(x)F(x)<H( x )G(x) 同解;如果H(x)<0,那么不等式F(x)<G(x)与不等式H (x)F(x)>H(x)G(x)同解。







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