怎么绘制直角ABC三角形，AB等于100，角B为30°。请写出绘制过程。
\u5df2\u77e5\u76f4\u89d2\u4e09\u89d2\u5f62abc.ab\u957f100\uff0c\u2220b90º\u2220a30º\u3002\u90a3bc\u957f\u591a\u5c11\u2220c=180\u00b0-\u2220b-\u2220a=60\u00b0
\u6b63\u5f26\u5b9a\u7406\uff1aab/sinc=bc/siana
\u5219bc=ab*sina/sinc=100sin30\u00b0/sin60\u00b0=100\u221a3/3
(1)\u8fc7M\u4f5cMN\u22a5AC\u4ea4AC\u4e8eN\uff0c \u2235BC=6\uff0c\u2220A=30\u00b0\uff0c \u2234AB=12\uff0cAC=\u221a\uff0812??-6??\uff09=6\u221a3\uff0c \u7531AM=4\uff0c\u2234MN=2\uff0c \u7531CD=x\uff0c\u2234AD=6\u221a3-x\uff0c \u25b3ADM\u9762\u79ef\u4e3ay=1/2\u00b72\u00b7\uff086\u221a3-x\uff09 \u2234y=6\u221a3-x\u3002 (2)\u5b9a\u4e49\u57df\u4e3a\uff1a0\uff1cx\uff1c6\u221a3.9573
这样画：
C是直角，AB=100 AC=50 BC=50*根号3
绛旓細鍥炵瓟锛欳鏄鐩磋,AB=100 AC=50 BC=50*鏍瑰彿3
绛旓細鐪嬪浘
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