用C语言编程实现从键盘任意输入10个整数，统计其中奇数的个数，并计算这些奇数的和。 C语言：输入10个整数,求出它们的和,统计其中偶数的个数,输...
\u7528C\u8bed\u8a00\u7f16\u7a0b\u5b9e\u73b0\u4ece\u952e\u76d8\u4efb\u610f\u8f93\u516510\u4e2a\u6574\u6570,\u7edf\u8ba1\u5176\u4e2d\u5947\u6570\u7684\u4e2a\u6570,\u5e76\u8ba1\u7b97\u8fd9\u4e9b\u5947\u6570\u7684\u548c#include
main()
{
int i,n=0,sum=0;
int a[10];
printf("n\\u8f93\u516510\u4e2a\u6570:");
for(i=0;i<10;i++)
scanf("%d",&a[i]);
for(i=0;i<10;i++)
{
if(a[i]/2!=0)
{
n++;
sum+=a[i];
}
}
printf("%d",n,sum);
}
\u5148\u8bd5\u8bd5\u770b\u53ef\u4ee5\u5417\uff1f\u6211\u597d\u4e45\u6ca1\u6709\u5199\u6570\u7684\u8f93\u5165\u548c\u8f93\u51fa\u4e86\uff0c\u4f60\u7f16\u8bd1\u770b\u53ef\u4ee5\u5417\uff1f\u4e0d\u884c\u518d\u544a\u8bc9\u6211\u7ed9\u4f60\u6539\u3002
#include
#defineN10
inti;
voidsum(inta[])
{
intsum_num=0;
for(i=0;i<N;i++)
{
sum_num+=a[i];
}
printf("\u548c=%d\n",sum_num);
}
voidcheck(inta[])
{
intone=0,two=0;
printf("\u5947\u6570\uff1a");
for(i=0;i<N;i++)
{
if(a[i]%2==0)
two++;
else
{
printf("%d",a[i]);
one++;
}
}
printf("\n\u5947\u6570\u4e2a\u6570=%d\n\u5076\u6570\u4e2a\u6570=%d",one,two);
}
intmain()
{
intnum[N]={0};
for(i=0;i<N;i++)
scanf("%d",&num[i]);
sum(num);
check(num);
}
\u6269\u5c55\u8d44\u6599
C\u8bed\u8a00\u7edf\u8ba1\u82f1\u6587\u5b57\u6bcd\u3001\u7a7a\u683c\u3001\u6570\u5b57\u548c\u5176\u5b83\u5b57\u7b26\u7684\u4e2a\u6570
#include"stdio.h"
voidmain()
{
charc;
intletters=0,space=0,digit=0,others=0;
printf("pleaseinputsomecharacters\n");
while((c=getchar())!='\n')
{
if(c>='a'&&c='A'&&c<='Z')
letters++;
elseif(c=='')
space++;
elseif(c>='0'&&c<='9')
digit++;
else
others++;
}
printf("allinall:char=%dspace=%ddigit=%dothers=%d\n",letters,
space,digit,others);
}
void main()
{
int a[10],i,n=0,sum=0;
printf("请输入十个整数：");
for(i=0;i<10;i++)
{
scanf("%d",&a[i]);
if(a[i]%2!=0)
{
n++;
sum=sum+a[i];
}
}
printf("共有%d个奇数，它们的和是：%d\n",n,sum);
}
楼上两位同学方法都对。但第二种方法用数组完全没必要。
int main()
{
int temp; /* 用于临时保存输入的整数*/
int sum = 0; /*用于求和*/
int count = 0;
int i;
/* 输入这10个数*/
for (i = 0; i < 10; i++)
{
scanf("%d", &temp);
if (temp % 2)
{
count++;
sum += temp;
}
}
printf("the count of odd num is %d, sum is %d\n", count, sum);
return 0;
}
绛旓細int main(){ int a,b,c;int max;cout<<"璇杈撳叆涓変釜鏁";cin>>a>>b>>c;if(a>b){ max = b;if(c > max)max = c;} else { max = a;if(c > max)max = c;} cout<<"鏈澶у兼槸"<<c<<endl;return 0;}
绛旓細绋嬪簭濡備笅锛#include<stdio.h>#define MAXSIZE 10main(){int a[MAXSIZE];int k;printf("please inter ten number:");for(k=0;k<MAXSIZE;k++){ scanf("%d",&a[k]);} Fun(a);for(k=0;k<MAXSIZE;k++)printf("%d,",a[k]);} void Fun(int a[]){ int i;int temp;int MaxNu...
绛旓細int main(){ int n,k=0;int a[11]={0};scanf("%d",&n);while(n){ a[k++]=n%10;//鎻愬彇鍚勪釜浣嶄笂鐨勬暟锛屽偍瀛樺湪鏁扮粍a涓 n/=10;} for(int i=0;i<k;i++)//鍐掓场鎺掑簭 for(int j=0;j<k-i-1;j++)if(a[j]>a[j+1]){ int t;t=a[j];a[j]=a[j+1];a[j+1]=...
绛旓細void main(){ int a[10];int i,j,max,min,temp,m,n;printf("璇杈撳叆鍗佷釜鏁存暟\n");for(i=0;i<10;i++){ scanf("%d",&a[i]);} for(i=0;i<10;i++){ printf("%d ",a[i]); //瑕佸姞绌烘牸 } printf("\n"); //鎹㈣ max=a[0];min=a[0];m=0; n=0; //...
绛旓細鎬濊矾锛氬畾涔変竴涓瓧绗︽暟缁勶紝鍒╃敤璇ユ暟缁勬帴鏀閿洏杈撳叆鐨勬暣鏁帮紝鎺ョ潃渚濇閬嶅巻璇ユ暟缁勫苟杈撳嚭銆傚弬鑰冧唬鐮侊細include "stdio.h"int main(){ int i;char a[100];gets(a);//鎺ユ敹閿洏杈撳叆 printf("%c",a[0]);//鍏堣緭鍑虹涓涓瓧绗 for(i=1;a[i]!='\0';i++)//鎺ョ潃杈撳嚭鍚勪釜瀛楃 printf("$%c"...
绛旓細,n=0,i,sum=0; for(i=0;i<20;i++) scanf("%d",&a[i]);//杈撳叆20涓暟 for(i=0;i<20;i++) { if(a[i]>=0) { n++;//缁熻闈炶礋鏁扮殑涓暟 sum+=a[i];//闈炶礋鏁扮殑鍜 } } printf("涓暟锛%d 鍜岋細%d",n,sum);} ...
绛旓細{ int t,i;t=sqrt(num)+1;for(i=2;i<t;i++){ if(num%i==0)break;} if(i==t)return 1;return 0;} int main(){ int n;printf("璇杈撳叆浠绘剰涓涓鏁存暟:");scanf("%d",&n);if (shu(n))printf("\n%d鏄礌鏁!",n);else printf("\n%d涓嶆槸绱犳暟!",n);return 1;} ...
绛旓細) { if ( *r>='0' && *r<='9' ) { *p=*r; p++; } else if ( *r>='a' && *r<='z' ) { *q=*r; q++; } else if ( *r>='A' && *r<='Z' ) { *q=*r; q++; } r++; } *p=*q=0; printf("%s\n%s\n",str1,str2);} ...
绛旓細杈撳叆3涓瓧绗︿覆锛屾寜浠庡皬鍒板ぇ椤哄簭杈撳嚭銆 //鍏鐢ㄧ▼搴瀵逛笁涓暟杩涜浠庡皬鍒板ぇ鎺掑簭锛岀劧鍚庝慨鏀圭▼搴#include<stdio.h>#include<string.h>int main(){void swap(char *pt1,char *pt2); char a[20],b[20],c[20]; char *p1,*p2,*p3; printf("璇疯緭鍏ヤ笁涓瓧绗︿覆:"); gets(a); gets(b); ...
绛旓細int sum=0;printf("璇杈撳叆涓涓ぇ浜2鐨勬暣鏁帮細");scanf("%d",&n);l=n;for(;n>=2;n--){ for(i=2;i<n;i++){ if(n%i!=0)//鍒ゆ柇鍏朵负绱犳暟 t=1;else { t=2;break;} } if(t==1){ sum+=n;//printf("%d ",n);//杈撳嚭1-n涔嬮棿鐨勬墍鏈夌礌鏁 } } printf("1-%d涔嬮棿鐨勬墍鏈...
