有一个3*4的矩阵，要求编程求出其中最大的那个元素的值，以及其所在的行号和列号。从键盘输入矩阵元素值 有一个3*4的矩阵，要求编程序求出其中值最大的那个元素的值，...
\u6709\u4e00\u4e2a3*4\u7684\u77e9\u9635\uff0c\u8981\u6c42\u7f16\u7a0b\u5e8f\u6c42\u51fa\u5176\u4e2d\u503c\u6700\u5927\u7684\u90a3\u4e2a\u5143\u7d20\u7684\u503c\uff0c\u4ee5\u53ca\u5176\u6240\u5728\u7684\u884c\u53f7\u548c\u5217\u597d#include
void main()
{int a[3][4]={{1,2,3,4},{5,6,7,8},{9,10,11,12}};
int i,j,c,d,max;
max=a[0][0];
for(i=0;i<3;i++)
{for(j=0;j<4;j++)
if(max<=a[i][j])
{max=a[i][j];
c=i;
d=j;
}
}
printf("%d\u6700\u5927\u6570\n%d\u884c\u53f7\n%d\u5217\u53f7",max,c,d);
}
#include
void main()
{int a[3][4]={{1,2,3,4},{5,6,7,8},{9,10,11,12}};
int i,j,c,d,max;
max=a[0][0];
for(i=0;i<3;i++)
{for(j=0;j<4;j++)
if(max<=a[i][j])
{max=a[i][j];
c=i;
d=j;
}
}
printf("%d\u6700\u5927\u6570\n%d\u884c\u53f7\n%d\u5217\u53f7",max,c,d);
}
{
int i,j row=0,colum=0,max;
int a[3][4]={{1,2,3,4},{9,8,7,6},{-10,10,-5,2}};
max=a[0][0];
for(i=0;i<=2;i++)
for(j=0;j<=3;j++)
if(a[i][j]>max)
{
max=a[i][j];
row=i;
colum=j;
}
printf("max=%d,row=%d,colum=%d\n",max,row,colum);
}你可以搜索 编，程，回，忆，录，之unity3d学习了解下，我觉得这个课程很不错，容易学
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绛旓細鎴戞潵 include <stdio.h> include "stdlib.h"include "time.h"main(){ int i,j,*p,arry[3][4];p=arry[0];srand((unsigned)time(NULL));for (i=0;i<3;i++){ for (j=0;j<4;j++){ arry[i][j] = rand()%100+1;} } printf("\n ---");while(*p){ printf("%d ",*p...
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绛旓細clear dime a(3,4)for i=1 to 3 for j=1 to 4 input "璇疯緭鍏涓涓鍊硷細" to a(i,j)endfor endfor k=a(1,1)for m=1 to 3 for n=1 to 4 r=a(m,n)if r>k k=r x1=m x2=n endif endfor endfor ?"鍏朵腑鏈澶х殑鍊兼槸锛",k ?"瀹冩墍鍦ㄧ殑浣嶇疆鏄"+alltrim(str(x1))+...
绛旓細package com.javase.test.demo;import java.util.Random;public class XXX { public static void main(String args[]) { int array[][] = new int[3][4];for (int i = 0; i < 3; i++) { for (int j = 0; j < 4; j++) { array[i][j] = new Random().nextInt(100);...
绛旓細include<stdio.h> main(){ int i,j,a[3][4],min,mi,mj;for(i=0;i<3;i++)for(j=0;j<4;j++)scanf("%d",&a[i][j]);mi=mj=0;min=a[0][0];for(i=0;i<3;i++)for(j=0;j<4;j++){ if(min>a[i][j]){ min=a[i][j];mi = i;mj = j;} } printf("...
