丧心病狂的线代证明题，来位大佬帮忙啊啊啊啊 ((((;°Д°))))
Bilibili\u4e27\u5fc3\u75c5\u72c2\u7684\u95ee\u9898\u53c8\u6765\u4e86-_-||| \u6c42\u7b54\u6848\u554a\u554a\u554a\u554a\u53e4\u6cb3\u65e9\u82d7
\u5929\u72d7
\u300a\u6d6e\u58eb\u5fb7\u300b
\u674f\u5b50\u5fa1\u6d25
\u742a\u9732\u8bfa
\u79c0\u5409
Stallman
4
\u8f66\u7530\u6b63\u7f8e
Absolute Terror Field
2
\u56db\u559c
\u5408\u91d1\u88c5\u5907
4
\u68b6\u6d66\u7531\u8bb0
\u5207\u5229\u6b27
\u2468
\u84dd\u767d\u6761\u7eb9\u80d6\u6b21
\u6c1f\u9511\u9178
\u6770\u6d1b\u00b7\u8c22\u76ae\u5229
4
48
\u523a\u5ba2\u4fe1\u6761
\u6728\u5409\u30ab\u30ba\u30e4
\u8f9b\u5df4\u5fb7
\u671b\u91c7\u7eb3\uff01\uff01\uff01\uff01\uff01\uff01\uff01\uff01\uff01\uff01
#include#define N 10000//N\u592a\u5927 //\u4f7f\u7528\u4e4b\u524d\u8981\u5148\u5b9a\u4e49\u6216\u58f0\u660e int xy(int *x,int y){ int m=0,*p; for(p=x;p<x+y;p++) m+=*p; return m;}int main(){ int c,a[N],i; scanf("%d",&c);//\u8981\u52a0& for(i=0;i<c;i++){ scanf("%d",&a[i]);} xy(a,c); printf("%d",xy(a,c));return 0;}
19. 设 A 的特征值为 λ1，λ2， 则λ1+λ2 = tr(A) = 8, λ1λ2 = |A| = 12,
则A 的两个特征值分别是2， 6.
21. (1) (AB)x = λx, B(AB)x = λBx,
(BA)(Bx) = λ(Bx), 即 (BA)y = λy
则 λ 也是 BA 的特征值。
(2) λ = 0 是 AB 的特征值，则 |AB| = |A||B| = 0，
|BA| = |B||A| = 0，则λ = 0 也是 BA 的特征值。
23. P^(-1)AP = ∧(对角阵), P^(-1)BP = D(对角阵),
得 A = P∧P^(-1), B = PDP^(-1)，∧D = D∧
AB = P∧P^(-1)PDP^(-1) = P∧DP^(-1),
BA = PDP^(-1)P∧P^(-1) = PD∧P^(-1)，
得 AB = BA
绛旓細19. 璁 A 鐨勭壒寰佸间负 位1锛屛2锛 鍒 位1+位2 = tr(A) = 8, 位1位2 = |A| = 12,鍒橝 鐨勪袱涓壒寰佸煎垎鍒槸2锛 6.21. (1) (AB)x = 位x, B(AB)x = 位Bx,(BA)(Bx) = 位(Bx), 鍗 (BA)y = 位y 鍒 位 涔熸槸 BA 鐨勭壒寰佸笺(2) 位 = 0 鏄 AB 鐨...
绛旓細鎵浠^2=1/4(B^2+2B+E)鍙堝洜涓築^2=E 鎵浠^2=1/4(2B+2E)=1/2(B+E)=A
绛旓細R(AB)<=R(A)锛屽張鍥犱负A鐨勭З涓嶅彲鑳借秴杩噈,n涓殑杈冨皬鍊硷紝鎵浠 R(AB)<=R(A)<=n 鎵浠ユ渶缁堬紝R(AB)<=n<m AB涓嶆弧绉╋紝閭ｅ綋鐒惰鍒楀紡涓0
绛旓細姹傜壒寰佸肩殑鏂圭▼锛屽氨鎶夾鏇挎崲涓何伙紝E鏇挎崲涓1 A^2 +A=2E鍗矨^2 +A-2E=0 鍐欏嚭鐗瑰緛鍊兼柟绋嬪紡 鍗澄籢2+位-2=0锛岃В寰桝鐨勭壒寰佸间负 -2鎴1 鑰寍A|=4锛岃鍒楀紡鍊肩瓑浜庢墍鏈夌壒寰佸肩殑涔樼Н 鏄剧劧鐢-2鍜1缁勫悎鎴愪笁涓暟锛屽彧鏈 (-2)*(-2) *1绛変簬4 浜庢槸鐗瑰緛鍊间负-2锛-2锛1 閭ｄ箞瑙勮寖鍨嬩负涓や釜 -1锛...
绛旓細璇佹槑锛氬洜涓哄鏁版瀹炵郴鏁板椤瑰紡褰㈠锛歛(2n-1)x^(2n-1)+a(2n-2)x^(2n-2)+鈥︹+a2x^2+a1x+a0=0 鍏朵腑鏈楂樻椤圭郴鏁癮(2n-1)鈮0 浠(x)=a(2n-1)x^(2n-1)+a(2n-2)x^(2n-2)+鈥︹+a2x^2+a1x+a0 濡傛灉a(2n-1)>0,鍒欏綋x->+鈭炴椂,f(x)->+鈭烇紱褰搙->-鈭炴椂,f(x)-...
绛旓細涓涓柟闃电殑琛屽垪寮忕殑鍊煎氨绛変簬鍏舵墍鏈夌壒寰佸肩殑杩炵画涔樼Н 鍦ㄨ繖閲 涓夐樁鏂归樀A婊¤冻锝淎锝=锝淎+E锝=锝淎+2E锝=0,寰堟樉鐒禔鐨3涓壒寰佸煎氨鏄0,-1,-2 閭ｄ箞A+3E鐨3涓壒寰佸煎氨鏄0+3,-1+3,-2+3鍗3,2,1 鎵浠 |A+3E|= 3脳2脳1=6
绛旓細銆愯В绛斻慉锛孊閮芥槸鍙嗙煩闃点傛牴鎹煩闃靛叕寮 A*A= | A | E |AB|E=(AB)*AB |AB|E=|A| |B|E=|A|B*B=B*|A|EB=B*(A*A)B=B*A*AB 鍗 (AB)*AB=B*A*AB A锛孊閮芥槸鍙嗙煩闃点傜瓑寮忎袱绔彸涔楤^-1锛孉^-1 鎵浠(AB)*=B*A newmanhero 2015骞1鏈20鏃12:11:47 甯屾湜瀵逛綘鏈...
绛旓細璇佹槑: 鍥犱负detA=1, 鎵浠鍙.鎵浠 A 鍙粡Eij(c)鍨嬭鍙樻崲鍖栦负涓婁笁瑙掔煩闃.涓旂敱 det(A)=1, 涓诲瑙掔嚎涓婂厓绱犲繀鐒堕兘鏄1.鍐嶇粡Eij(c)鍨嬭鍙樻崲鍗冲彲鍖栦负鍗曚綅鐭╅樀E.鎵浠ュ瓨鍦‥ij(c)鍨嬪垵绛夌煩闃礟1,...,Ps浣垮緱 P1...PsA=E.鎵浠 A = (P1...Ps)^-1 = Ps^-1...P1^-1.鐢变簬Eij(c)鍨嬪垵绛...
绛旓細鑻=2 w1=a1v1+a2v2 w2=b1v1+b2v2 w3=c1v1+c2v2 鑱旂珛1銆2 b2w1-a1w2=(a1b2-a2b1)v1 a1b2-a2b1闈為浂鍥犱负independent 鑱旂珛2銆3 c2w2-b1w3=(b1c2-b2a1)v1 鍚屼笂 鎵浠 锛坆1c2-b2a1锛塨2w1+???w2+ (a1b2-a2b1)b1w3=0 鎵浠2=0 b1=0 瀵圭О鎬у緱a1=a2=b1=b2=c1=...
绛旓細璇佹槑锛氬洜涓簉(AB)鈮(B)鍙堝洜涓篈B=E锛屾墍浠(AB)=m锛岃宺(B)鈮 閭ｄ箞r(B)=m 鎵浠鍒楁弧绉╋紝鎵浠鐨勫垪鍚戦噺绾挎ф棤鍏炽傝瘉姣曘俷ewmanhero 2015骞5鏈30鏃00:30:26 甯屾湜瀵逛綘鏈夋墍甯姪锛屾湜閲囩撼銆
