编程题:1:定义含有10个元素的数组,并将数组中的元素按逆序从新存放后输出。 用C++做 从键盘上输入10个整数存入一维数组元素中,然后按逆序输出该数...

C++\u7f16\u7a0b\u9898\uff1a 1\uff0e\u5b9a\u4e49\u4e00\u4e2a\u4e00\u7ef4\u6570\u7ec4\uff0c\u628a\u5404\u5143\u7d20\u503c\u8d4b\u4e3a\u5176\u4e0b\u6807\u503c\uff0c\u5e76\u53cd\u5411\u8f93\u51fa\u5404\u5143\u7d20\u503c\u3002 \u6c42\u5199\u7a0b\u5e8f

//--------\u7b2c\u4e00\u9898-------------
#include
using namespace std;
int main()
{
int a[10];
for(int i= 0; i< 10; i++)
a[i]= i;
for(i= 9; i>= 0; i--)
cout<<a[i]<<' ';
cout<<endl;
return 0;
}
//--------\u7b2c\u4e8c\u9898-------------
#include
using namespace std;
char* catstr(char* des, char* res)
{
int len_des= 0;
while(des[len_des++]);
len_des--;
for(int i= 0; res[i]; i++)
des[len_des++]= res[i];
des[len_des++]= 0;
return des;
}
void main()
{
char s1[50]= "abcdefg", s2[]= "12345";
catstr(s1, s2);
cout<<s1<<endl;
}

/*\u8fd8\u53ef\u4ee5\u7528\u8d77\u6ce1\u6392\u5e8f\u7b97\u6cd5\u6216\u8005\u4e8c\u53c9\u6392\u5e8f\u7b49\uff0c
\u5177\u4f53\u7b97\u6cd5\u53ef\u4ee5\u53bb\u770b\u6570\u636e\u7ed3\u6784\u6392\u5e8f\u4e00\u7ae0\u7684\u5185\u5bb9*/
#include //\u7b80\u5355\u9009\u62e9\u6392\u5e8f
using namespace std;

int main()
{
int i,j,temp;
int a[10];
bool flag = true;//\u5982\u679c\u57289\u8d9f\u4e4b\u524d\u5df2\u7ecf\u6709\u5e8f\u5c31\u4e0d\u7528\u518d\u7ee7\u7eed\u4e86
for(i = 0;i < 10;i++)//\u8f93\u5165
cin>>a[i];
for(i = 0;i < 9;i++)//\u6700\u591a\u8fdb\u884c9\u8d9f
{
for(j = i+1;j < 10;j++)
if(a[i] < a[j])
{
temp = a[i];
a[i] = a[j];
a[j] = temp;
flag = false;
}
if(flag)
break;//\u8df3\u51fa\u5916\u5c42\u5faa\u73af
flag = true;
}
for(i = 0;i < 10;i++)//\u8f93\u51fa
cout<<a[i]<<' ';
cout<<endl;
system("PAUSE");
return 0;
}

#include <stdio.h>
void main()
{
int i, j, a[10],temp;
for (i = 0; i < 10; i++)
scanf("%d",&a[i]);
printf("\n");
for (i = 0; i < 9; i++)
for (j = i+1; j < 10; j++)
if (a[j]<a[i])
{
temp = a[i];
a[i] = a[j];
a[j] = temp;
}
for (i = 0; i < 10; i++)
printf("%3d",a[i]);
}

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