若函数f(x)为偶函数,且y=f(x+1)为奇函数,f(2)=-1,则f(1)+f(2)+..... 若函数f(1+x)为偶函数,f(x-2)为偶函数,则y=f(...

\u82e5\u51fd\u6570f\uff08x\uff09\u7684\u5b9a\u4e49\u57df\u4e3aR\uff0c\u4e14\u6ee1\u8db3y=f\uff08x+1\uff09\u4e3a\u5947\u51fd\u6570\uff0cy=f\uff08x-1\uff09\u4e3a\u5076\u51fd\u6570\uff0c\u5219\u4e0b\u5217\u8bf4\u6cd5\u4e2d\u4e00\u5b9a\u6b63\u786e\u7684\u6709___

\uff081\uff09\u2235y=f\uff08x-1\uff09\u4e3a\u5076\u51fd\u6570\uff0c\u5373\u5bf9\u79f0\u8f74\u4e3ax=0\uff0c\u5c06y=f\uff08x-1\uff09\u7684\u56fe\u8c61\u5411\u5de6\u5e73\u79fb\u4e00\u4e2a\u5355\u4f4d\u5373\u5f97y=f\uff08x\uff09\u7684\u56fe\u8c61\u5173\u4e8e\u76f4\u7ebfx=-1\u5bf9\u79f0\uff0c\u2234\u6545\uff081\uff09\u6b63\u786e\uff1b\uff082\uff09y=f\uff08x+1\uff09\u4e3a\u5947\u51fd\u6570\uff0c\u5373\u5bf9\u79f0\u4e2d\u5fc3\u4e3a\uff080\uff0c0\uff09\uff0c\u5c06y=f\uff08x+1\uff09\u7684\u56fe\u8c61\u5411\u53f3\u5e73\u79fb\u4e00\u4e2a\u5355\u4f4d\u5373\u5f97y=f\uff08x\uff09\u7684\u56fe\u8c61\u5173\u4e8e\u70b9\uff081\uff0c0\uff09\u5bf9\u79f0\uff0c\u2234f\uff08-x\uff09=-f\uff08x+2\uff09\u2460\u2235y=f\uff08x\uff09\u7684\u56fe\u8c61\u5173\u4e8e\u76f4\u7ebfx=-1\u5bf9\u79f0\uff0c\u2234f\uff08-x\uff09=f\uff08x-2\uff09\u2461\u7531\u2460\u2461\u53ef\u5f97\uff0cf\uff08x+2\uff09=-f\uff08x-2\uff09\uff0c\u5c06x\u4ee3\u6362\u4e3ax+2\uff0c\u5f97f\uff08x+4\uff09=-f\uff08x\uff09\uff0c\u518d\u5c06x\u4ee3\u6362\u4e3ax+4\uff0c\u5f97f\uff08x+8\uff09=-f\uff08x+4\uff09=f\uff08x\uff09\uff0c\u2234f\uff08x\uff09\u7684\u5468\u671f\u4e3a8\uff0c\u6545\uff082\uff09\u9519\u8bef\uff1b\uff083\uff09\u6839\u636e\u51fd\u6570\u7684\u5468\u671f\u4e3a8\uff0c\u2234f\uff082013\uff09=f\uff085\uff09\uff0c\u2235f\uff08x+4\uff09=-f\uff08x\uff09\uff0c\u2234f\uff085\uff09=-f\uff081\uff09\u2235f\uff08-x\uff09=-f\uff08x+2\uff09\uff0c\u6240\u4ee5f\uff081\uff09=-f\uff081\uff09\u5373f\uff081\uff09=0\uff0c\u2234f\uff082013\uff09=0\uff0c\u6545\uff083\uff09\u6b63\u786e\uff1b\uff084\uff09\u7531\uff083\uff09\u53ef\u77e5f\uff081\uff09=f\uff08-3\uff09=f\uff085\uff09=0\uff0c\u82e5\u5f53f\uff080\uff09=0\u65f6\uff0c\u5219f\uff082\uff09=0\uff0cf\uff08-2\uff09=0\u6545f\uff08x\uff09\u5728[-2\uff0c2]\u4e0a\u4e0d\u6b62\u4e00\u4e2a\u96f6\u70b9\uff0e\u6545\uff084\uff09\u4e0d\u4e00\u5b9a\u6b63\u786e\u6545\u7b54\u6848\u4e3a\uff1a\uff081\uff09\uff083\uff09\uff0e

\u7279\u5f811\uff0c\u5bf9\u79f0\u8f74\uff1a
\u5bf9\u79f0\u51fd\u6570\u4f53\u73b0\u4e3a\uff0cf(a+x)=f(a-x)\u65f6\uff0cf(x)\u5173\u4e8ex=a\u8f74\u5bf9\u79f0\uff0c
f(1+x)\u4e3a\u5076\u51fd\u6570\uff0cf(1+x)=f(1-x)\uff0c\u6240\u4ee5f(x)\u5173\u4e8ex=1\u8f74\u5bf9\u79f0\uff0c
f(x-2)\u4e3a\u5076\u51fd\u6570\uff0cf(x-2)=f(-2+x)=f(-2-x)\uff0c\u6240\u4ee5f(x)\u5173\u4e8ex=-2\u8f74\u5bf9\u79f0\uff0c
\u7279\u5f812\uff0c\u5468\u671f\uff1a
\u5982\u679cf(x)=f(x+T)\uff0c\u5219\u51fd\u6570f(x)\u662f\u5468\u671f\u4e3aT\u7684\u5468\u671f\u51fd\u6570\uff0c
f(1+x)=f(x+1)=f((x+3)-2)=f(-2-(x+3))=f(-5-x)=f(1+(-6-x))=f(1-(-6-x))=f(7+x)=f(x+7)\uff0c
\u51fd\u6570f(x)\u662f\u5468\u671f\u51fd\u6570\uff0c\u5468\u671fT=7-1=6\uff0c

f(x-1)是f(x)向右平移一个单位得到,它关于原点对称,说明f(x)关于(-1,0)对称
f(x-1)=-f(-x-1) x用x+1代 f(x)=-f(-x-2)=f(-x) , -x用x代 -f(x-2)=f(x)
再写一个 -f(x-4)=f(x-2) 上两式一合并 得f(x)=f(x-4),周期为4

f(1)=f(-1)=0,f(2)=-1,f(3)=f(-1)=0,f(4)=f(0)=-f(-2)=-f(2)=1
故有f(1)+f(2)+f(3)+f(4)=0-1+0+1=0
2014/4=503...2
故有f(1)+f(2)+...+f(2014)=f(1)+f(2)=0-1=-1

f(1)+f(2)+.....f(1)+f(2)+......+f(2014)是一直加到f(2014)?



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