为啥x1-x2的绝对值=根下D方-4F? 急求!!为什么x1-x2的绝对值=根号下(x1+x2)的平方...

\u4e3a\u4ec0\u4e48x1-x2\u7684\u7edd\u5bf9\u503c=\u6839\u53f7\u4e0b\u7684\u5e73\u65b9

\u8fd9\u5c5e\u4e8e\u97e6\u8fbe\u5b9a\u7406\u7684\u62d3\u5c55\u3002 \u9996\u5148\u53ef\u4ee5\u7528\u4e8e\u6c42|x1-x2| \u5176\u6b21 \u5728\u89e3\u6790\u51e0\u4f55\u4e2d \u5e38\u5e94\u7528 \u5c24\u5176\u662f\u5728\u76f4\u7ebf\u548c\u66f2\u7ebf\u76f8\u4ea4\u6c42\u4ea4\u70b9\u95f4\u7ebf\u6bb5\u957f\u5ea6\u65f6\u3002


|x1-x2|=√(x1+x2)^2-4x1x2
然后大概是利用二元一次方程根与系数的关系,可以得
x1+x2=D
x1x2=F
带入即可。

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