函数f(x)=sin^2x求导 f(x)=sin2x怎么求导?

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f(x) = sin2x = sinu, \u5176\u4e2d u = 2x
f'(x) = cosu\u00b7(u)' = cos2x (2x)' = 2cos2x

∵f(x)=sin^2x=(1-cos2x)/2
∴f'(x)=sin2x

f'(x)=2sinx*cosx=sin(2x)

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