sin2xcos2x怎么化简？ asin2x+bcos2x怎么化简

sin2x+cos2x\u600e\u4e48\u5316\u7b80

sin2x+cos2x
= \u221a2\u00b7\u3010cos45\u00b7sin2X + sin45\u00b7cos2X\u3011
= \u221a2\u00b7sin[2X + 45]


\u5bf9\u5427 \u52a0\u6cb9

\u5229\u7528\u8f85\u52a9\u89d2\u516c\u5f0f\uff1a
f(x)=asin2x+bcos2x
=[\u221a(a²+b²)]{[a/(a²+b²)]sin2x+[b/\u221a(a²+b²)]cos2x}
=[\u221a(a²+b²)]sin(2x+\u03b8)

你是要化简成什么样的啊
y=sin2xcos2x=1/2sin4x，这个可以不？
请采纳答案，支持我一下。

公式sin2x=2sinxcosx y=sin2xcos2x=1/2sin4x

=1/2sin4x

1/2*sin4x

sin2x cos2x鎬庝箞鍖栫畝
绛旓細sin2x cos2x =(1/2)sin4x

鍑芥暟y=sin2xcos2x鎬庝箞鍖栫畝
绛旓細=sin2xcos2x =(1/2)*2sin2xcos2x =(1/2)*sin4x PS锛氫害鍙互鍖栦负鍏跺畠褰㈠紡

y=sin2xcos2x鎬庝箞鍖栫畝?
绛旓細y=sin(2x)cos(2x)=(1/2)sin(4x)

y=sin2xcos2x鍖栫畝鎬庝箞鍒皔=sin4x/2鐨,瑕佸叿浣撴楠
绛旓細涓夎鍑芥暟鍏紡sin2t=2sintcost (sin2t)/2=sintcost 浠2x=t y=sin2xcos2x=sintcost=(sin2t)/2 2t=4x 鎵浠 y=sin2xcos2x=锛坰in4x锛/2

y=sin2xcos2x鎬庝箞鍖栫畝
绛旓細鏍规嵁2鍊嶈鍏紡sin(2x)=2sinxcosx锛屽緱 y=sin2xcos2x=1/2(2sin2xcos2x)=1/2sin4x

y=sin2xcos2x鍖栫畝鎬庝箞鍒皔=sin4x/2鐨,
绛旓細涓夎鍑芥暟鍏紡sin2t=2sintcost (sin2t)/2=sintcost 浠2x=t y=sin2xcos2x=sintcost=(sin2t)/2 2t=4x 鎵浠 y=sin2xcos2x=锛坰in4x锛/2

sin2xcos2x鎬庝箞鍖栫畝?
绛旓細浣犳槸瑕鍖栫畝鎴愪粈涔堟牱鐨勫晩 y=sin2xcos2x=1/2sin4x锛岃繖涓彲浠ヤ笉锛熻閲囩撼绛旀锛屾敮鎸佹垜涓涓嬨

sin2x cos2x鎬庝箞鍖栫畝
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鍑芥暟sin2xcos2x 鐨勫鏁?
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鍖栫畝sin2x涔cos2x
绛旓細sin2x*cos2x =1/4*sin4x y=2cos鏂 涔榵闄や互2 +1???

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