数学高手请帮忙解答因式分解练习题！ 数学高手帮忙！！！（因式分解） 1-4(a+b)²...
\u6c42\u4e00\u9898\u6bd4\u8f83\u590d\u6742\u7684\u56e0\u5f0f\u5206\u89e3\u9898\u7684\u89e3\u9898\u8fc7\u7a0b\u00b7\u601d\u8def\u00b7\u7b54\u6848\uff01\uff08\u6570\u5b66\u9ad8\u624b\u8fdb\uff09\u89e3\uff1a(1+y)^2-2x^2(1+y^2)+x^4(1-y)^2
=(1+y)^2-2x^2(1+y)(1-y)+x^4(1-y)^2-4x^2y^2
=[(1+y)-x^2(1-y)]^2-4x^2y^2
=(1+y-x^2+x^2y)^2-(2xy)^2
=(1+y+2xy-x^2+x^2y)(1+y-2xy-x^2+x^2y)
=[(1-x^2)+(yx+y)+(x^2y+xy)][(1-x^2)-(xy-y)+(x^2y-xy)]
=(x+1)(x-1)(x-xy+1+y)(x-xy-1-y)
1-4(a+b)²
=(1+2a+2b)(1-2a-2b)
\uff08a²+9\uff09²-4a^4
=(a²+9+2a²)(a²+9-2a²)
=(3a²+9\uff09\uff089-a²)
=3(a²+3)(3+a)(3-a)
=5x(x^4-3x²y-4y²)
=5x(x²-4y)(x²+y)
3a2b2-17abxy+10x2y2
=(3ab-2xy)(ab-5xy)
5x5-15x3y-20xy2
=5x(x⁴－3x²y－4y²)
=5x(x²＋y)(x²－4y)
3a2b2-17abxy+10x2y2
=3(ab)²－17abxy＋(10xy)²
=(ab－5xy)(3ab－2xy)
不懂还可问，满意请及时采纳！o(∩_∩)o
5x^5-15x^3y-20xy^2
=5x(x^4-3x^2y-4y^2)
=5x(x^2-4y)(x^2+y)
3a^2b^2-17abxy+10x^2y^2
=(ab-5xy)(3ab-2xy)
1。提取公因式5x 即5x(x4-3x2y-4y2)=5x(x2+y)(x2-4y)
2.(3ab-2xy)(ab-5xy)
这两题的共同点就是把将简单的因式分解中的x,y变换成x2, ，xy, ab等
看不懂再问我
5xˆ5-15xˆ3y-20xyˆ2
=5x（xˆ4-3xˆ2y-4yˆ2）
=5x（xˆ2-4y）（xˆ2+y）
3aˆ2bˆ2-17abxy+10xˆ2yˆ2
=（3ab-2xy）（ab-5xy）
5x(X^4-3x^2y-4y^2)=5x(x^2-4y)(x^2+y)
(3ab-2xy)(ab-5xy)
要好好学习哦，希望能够帮助你！
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