若x-1的绝对值+(y+2)²=0,则(x+y)= (填数值)。(n为正整数) 若x-2的绝对值+(y+1)²=0,则y的x次方是...

\u82e5x-1\u7684\u7edd\u5bf9\u503c+(y+2)\u7684\u5e73\u65b9=0\uff0c\u5219\uff08x+y)\u76842011\u6b21\u65b9=

\u56e0\u4e3aX-1\u7684\u7edd\u5bf9\u503c\u52a0Y+2\u7684\u5e73\u65b9=0
\u53ea\u67090+0=0 \u6240\u4ee5X-1=0 Y+2=0

\u624d\u53ef\u4ee5X-1\u7684\u7edd\u5bf9\u503c\u52a0Y+2\u7684\u5e73\u65b9=0


\u5143\u65e6\u5feb\u4e50
\u671b\u91c7\u7eb3

x-1=0且y+2=0 所以 x=1 y=-2 所以 x+y=-1

x-1的绝对值+(y+2)²=0,x=1,y=-2
x+y=-1

1或-1

若x-1的绝对值+(y+2)²=0,则(x+y)=-1
若x-1的绝对值+(y+2)²=0,则(x+y)的次方n=1(n为偶数)
=-1 (n为奇数)

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