已知,二位随机变量(X,Y)相互独立,即有F(x,y)=F(x)F(y), 大学概率论题。 已知随机变量(X,Y)服从二维正态分布,其联...

\u5df2\u77e5\u4e8c\u7ef4\u968f\u673a\u53d8\u91cf(X,Y)\u7684\u8054\u5408\u5206\u5e03\u51fd\u6570\u4e3aF(x,y),\u5219P\uff08X>a,Y>b)=\uff3f\uff3f

\u7b54\u6848\u4e3a\uff1aF\uff08a\uff0cb\uff09+1-[F1\uff08a\uff09+F2\uff08b\uff09]
\u7531\u4e8eF\uff08a\uff0cb\uff09=P{X\u2264a\uff0cY\u2264b}\uff0cF1\uff08a\uff09=P{X\u2264a\uff0cY\uff1c+\u221e}\uff0cF2\uff08b\uff09=P{X\uff1c+\u221e\uff0cY\u2264b}\uff0c
\u800c\uff1a
P{X\uff1ea\uff0cY\uff1eb}=P{X\uff1c+\u221e\uff0cY\uff1c+\u221e}-P{X\u2264a\uff0cY\uff1c+\u221e}-P{X\uff1c+\u221e\uff0cY\u2264b}+P{X\u2264a\uff0cY\u2264b}
\u2234P{X\uff1ea\uff0cY\uff1eb}=1-F1\uff08a\uff09-F2\uff08b\uff09+F\uff08a\uff0cb\uff09=F\uff08a\uff0cb\uff09+1-[F1\uff08a\uff09+F2\uff08b\uff09]

\u6269\u5c55\u8d44\u6599\uff1a
\u8054\u5408\u6982\u7387\u5206\u5e03\u7684\u51e0\u4f55\u610f\u4e49\u4e0e\u5b9a\u4e49
\u8bbe(X,Y)\u662f\u4e8c\u7ef4\u968f\u673a\u53d8\u91cf\uff0c\u5bf9\u4e8e\u4efb\u610f\u5b9e\u6570x,y\uff0c\u4e8c\u5143\u51fd\u6570\uff1a
F(x,y) = P{(X P(X<=x, Y<=y)
\u79f0\u4e3a\uff1a\u4e8c\u7ef4\u968f\u673a\u53d8\u91cf(X,Y)\u7684\u5206\u5e03\u51fd\u6570\uff0c\u6216\u79f0\u4e3a\u968f\u673a\u53d8\u91cfX\u548cY\u7684\u8054\u5408\u5206\u5e03\u51fd\u6570\u3002
\u968f\u673a\u53d8\u91cfX\u548cY\u7684\u8054\u5408\u5206\u5e03\u51fd\u6570\u662f\u8bbe(X,Y)\u662f\u4e8c\u7ef4\u968f\u673a\u53d8\u91cf\uff0c\u5bf9\u4e8e\u4efb\u610f\u5b9e\u6570x,y\uff0c\u4e8c\u5143\u51fd\u6570\uff1aF(x,y) = P{(X P(X<=x, Y<=y)\u79f0\u4e3a\u4e8c\u7ef4\u968f\u673a\u53d8\u91cf(X,Y)\u7684\u5206\u5e03\u51fd\u6570\u3002
\u5982\u679c\u5c06\u4e8c\u7ef4\u968f\u673a\u53d8\u91cf(X,Y)\u770b\u6210\u662f\u5e73\u9762\u4e0a\u968f\u673a\u70b9\u7684\u5750\u6807\uff0c\u90a3\u4e48\u5206\u5e03\u51fd\u6570F(x,y)\u5728(x,y)\u5904\u7684\u51fd\u6570\u503c\u5c31\u662f\u968f\u673a\u70b9(X,Y)\u843d\u5728\u4ee5\u70b9(x,y)\u4e3a\u9876\u70b9\u800c\u4f4d\u4e8e\u8be5\u70b9\u5de6\u4e0b\u65b9\u7684\u65e0\u7a77\u77e9\u5f62\u57df\u5185\u7684\u6982\u7387\u3002

\u5148\u6839\u636exy\u7684\u4e8c\u7ef4\u5206\u5e03\u7684\u6807\u51c6\u5f62\u5f0f\u5206\u522b\u6c42x\u4e0ey\u7684\u5206\u5e03\uff08\u521d\u6b65\u4f30\u8ba1x\u4e0ey\u5e94\u8be5\u662f\u72ec\u7acb\u7684\uff09
\u7136\u540e\u6c42x2\u4e0ey2\u7684\u5206\u5e03 \u7531\u4e8ex\u4e0ey\u72ec\u7acb\uff0cx2\u4e0ey2\u4e5f\u72ec\u7acb\uff0c\u5c31\u53ef\u6c42z~N(\uff09\u7684\u671f\u671b\u548c\u65b9\u5dee\u4e86\uff0c\u7136\u540e\u5199\u4f5c\u6982\u7387\u5bc6\u5ea6\u5373\u53ef\u3002
\u671b\u91c7\u7eb3

F(x,y)=F(x)F(y)
∫[-∞→x]∫[-∞→y] f(u,v)dvdu=∫[-∞→x]f(u)du∫[-∞→y] f(v)dv
两边分别对x求偏导得:
∫[-∞→y] f(x,v)dv=f(x)∫[-∞→y] f(v)dv
两边分别对y求偏导得:
f(x,y)=f(x)f(y)

希望可以帮到你,不明白可以追问,如果解决了问题,请点下面的"选为满意回答"按钮,谢谢。

X,Y互相独立
设X的密度函数为f(x),Y的密度函数为f(y)
它们的联合密度函数为f(x,y)=f(x)f(y)
f(y,x)=f(y)f(x)=f(x,y)

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