C语言:班级有30个学生参加期末考试,求他们的平均分,并统计低于平均分的人数(平均分保留1位小数）？ C语言 输入一个班30人求平均分和超过平均分的人数
\u7528C\u8bed\u8a00\u8bbe\u8ba1\u4e00\u4e2a\u5b66\u751f\u6210\u7ee9\u7edf\u8ba1\u7a0b\u5e8f,\u8981\u6c42\uff081\uff09\u8f93\u516530\u4e2a\u5b66\u751f\u4e00\u95e8\u529f\u8bfe\u7684\u6210\u7ee9\u3002\uff082\uff09\u8ba1\u7b97\u73ed\u7ea7\u5e73\u5747\u5206\u3002#include"stdio.h"
void main()
{
int n=0;
int num;
int zf=0;
for(n=0;n<30;n++)
{
printf("\u8bf7\u8f93\u5165\u7b2c%d\u4e2a\u5b66\u751f\u7684\u6210\u7ee9:",n+1);
scanf("%d",&num);
zf+=num;
}
printf("\u8be5\u95e8\u529f\u8bfe\u7684\u73ed\u7ea7\u5e73\u5747\u5206\u4e3a:%d\n",zf/30);
}
#include
#define N 30
void main()
{
int i=0;
float ave,score[N],sum=0,p=0;
printf("\u8f93\u5165\u6210\u7ee9\uff1a\n");
for(i=0;i<N;i++)
{
scanf("%f",&score[i]);
sum+=score[i];
}
ave=sum/N;
printf("\u5e73\u5747\u6210\u7ee9\uff1a\n");
printf("%f\n",ave);
for(i=0;i<N;i++)
if(score[i]>ave)
p++;
printf("%d",p);
}
#define N 30
float average(float *scores, int size)
{
float aver = 0.0f;
for(int i = 0; i < size; i++)
aver += scores[i];
return aver / size;
}
int main()
{
float scores[N];
int sum = 0;
for(int i = 0; i < N; i++)
scanf("%f", &scores[i]);
float aver = average(scores, N);
printf("Average: %.1f\n", aver);
for(int i = 0; i < N; i++)
if(scores[i] < aver)
{
sum += 1;
printf("%3.1f ", scores[i]);
}
printf("\n总共有%d个人低于平均分。\n", sum);
return 0;
}
这是分分钟就能写出来的代码。
绛旓細printf("\n鎬诲叡鏈%d涓汉浣庝簬骞冲潎鍒嗐俓n", sum);return 0;}
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