c++程序输入字符串数组,找到字符串最后一个字符 如何用c++定义一个数组,并在数组中查找指定的字符

\u7528C++\u8bed\u8a00\u5b9e\u73b0\u8f93\u5165\u4e00\u4e2a\u5b57\u7b26\u4e32\u5c06\u6700\u540e\u4e00\u4e2a\u5b57\u7b26\u63d2\u5165\u5230\u5b57\u7b26\u4e32\u7684\u4e2d\u95f4\u540e\u8f93\u51fa\u957f\u5ea6\u4e0d\u8d85\u8fc7100\uff0c\u6025\uff01\uff01\uff01

\u4e00\u4e2a\u8981\u628a\u5b57\u7b26\u4e32\u5b9a\u4e49\u5b57\u7b26\u6570\u7ec4\uff0c\u4e0d\u5927\u4e8e100
Char str[100]
Len\u53d6\u51fa\u5b57\u7b26\u4e32\u957f\u5ea6\uff0c
\u957f\u5ea6\u51cf1\u5c31\u662f\u6700\u540e\u4e00\u4e2a\u5b57\u7b26\uff0c\u628a\u5b83\u7528temp\u5b58\u8d77\u6765\uff0c
\u7136\u540e\u7528\u5faa\u73af\u6765\u4ea4\u6362\u5b57\u7b26\uff0c\u5047\u5982\u7528for
For(i=len(str),i<len(str)/2,i--)
Temp=str[i-1];
Str[i-1]=str[i-2];
Str[i-2]=temp;
\u8fd9\u6837\u5c31\u53ef\u4ee5\u4e86
\u539f\u7406\u5c31\u662f\u4e0d\u65ad\u7684\u6570\u5b57\u4ea4\u6362\uff0c\u4ece\u6700\u540e\u4e00\u4f4d\u5f00\u59cb\uff0c\u4ea4\u6362\u5230\u4e2d\u95f4\u4e00\u4f4d\u5c31\u505c\u6b62\uff01

\u601d\u8def\uff1a\u5148\u5b9a\u4e49\u4e00\u4e2a\u5b57\u7b26\u6570\u7ec4\uff0c\u63a5\u7740\u8f93\u5165\u5b57\u7b26\u4e32\u8d4b\u503c\uff0c\u8f93\u5165\u9700\u8981\u67e5\u627e\u7684\u5b57\u7b26\uff0c\u904d\u5386\u5b57\u7b26\u6570\u7ec4\uff0c\u67e5\u627e\u8f93\u5165\u7684\u5b57\u7b26\uff0c\u5982\u679c\u627e\u5230\u505c\u6b62\u904d\u5386\u8f93\u51fa\u4f4d\u7f6e\uff0c\u5982\u679c\u904d\u5386\u7ed3\u675f\u8fd8\u6ca1\u627e\u5230\uff0c\u8f93\u51fa\u6ca1\u6709\u627e\u5230\u3002
\u53c2\u8003\u4ee3\u7801\uff1a
//\u53c2\u8003\u4ee3\u7801 #includeusing namespace std;int main(){char ch[100],c;int i;cin>>ch;cin>>c;for(i=0;i<strlen(ch);i++)if(ch[i]==c){cout<<i;break;}if(i==strlen(ch))cout<<"\u6ca1\u6709\u627e\u5230\uff01"; return 0;}/*\u8fd0\u884c\u7ed3\u679c\uff1adsafwera2*/

#include <stdio.h>

#include <string.h>

void find(char *str,char *data)

{

    int i=0;

 int j=0;

 int index;

 int flag=0;

 while(*(str+i)!='\0')

 {

  if(*(str+i)==*(data+j))

  {

   index=i;

   i++,j++;

   while(*(data+j)!='\0')

   {

               if(*(str+i)==*(data+j))

       i++,j++;

      else

       break;

   }

   if(*(data+j)=='\0')

   {

    printf("%d ",index);

    flag=1;

   }

   else

    i=index+1;

  }

  else

  {

   i++;

  }

  j=0;

 }

 if(flag==0)

  printf("No find!
");

 else

  printf("
");

}

int main()

{

 char *str ="This is a test of c program!";

 char data[80];

 scanf("%s",data);

 while(strcmp("###",data)!=0)

 {

  find(str,data);

        scanf("%s",data);

 }

 return 0;

}

运行效果如下:



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