观察下列数0.负二分之一.负三分之二.负四分之三,负五分之一,求2002数。若无限排列,则与数什么越来越近
0, -1/2, -2/3, -3/4, -4/5则 an=-(n-1)/n
n=2002时
a2002=-2001/2002
liman=lim-(n-1)/n=-1
与 -1 越来越近
绛旓細0, -1/2, -2/3, -3/4, -4/5 鍒 an=-(n-1)/n n=2002鏃 a2002=-2001/2002 liman=lim-(n-1)/n=-1 涓 -1 瓒婃潵瓒婅繎
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