若x-1的绝对值+（y+3）²+根号x+y+z=0，求x，y，z的值。 若X-1的绝对值+（y+3）的平方+根号x+y+z=0，求x...
x-1\u7684\u7edd\u5bf9\u503c+(y+3)\u7684\u5e73\u65b9+\u6839\u53f7x+y+z=0\u6c42x,y,z\u7684\u503c\u258fx-1\u258f+(y+3)²+\u221a(x+y+z)=0
x-1=0 x=1
y+3=0 y=-3
x+y+z=0 z=2
\u5e26\u7edd\u5bf9\u503c\u7684\u6570\uff0c\u67d0\u6570\u7684\u5e73\u65b9\u662f\u5927\u4e8e\u7b49\u4e8e0\u7684 \u6839\u53f7\u4e0b\u7684\u6570\u4e5f\u662f\u5927\u4e8e\u7b49\u4e8e0\u7684 \u82e5\u4e09\u4e2a\u6570\u52a0\u8d77\u6765\u7b49\u4e8e0\u7684\u8bdd\uff0c\u8fd9\u4e09\u4e2a\u5fc5\u987b\u90fd\u662f0
\u6240\u4ee5x=1 y=-3 z=2
所以x=1,y=-3，z=2
|x-1|+（y+3）²+√（x+y+z）=0
|x-1|>=0 （y+3）²>=0 √（x+y+z）>=0
可得|x-1|=0 （y+3）²=0 √（x+y+z）=0
x=1 y=-3 z=2
依题意可列方程组
x-1=0
y+3=0
3. x+y+z=0
解得
1.x=1
2.y=-3
3.z=2
绛旓細鍥犱负(x-1)鐨勭粷瀵瑰鏄ぇ浜庣瓑浜庨浂鐨勶紝(y+3)鐨勫钩鏂逛篃鏄ぇ浜庣瓑浜庨浂鐨勩傚綋杩欎袱涓畻寮忎箣鍜屼负0鏃讹紝璇存槑鍙瓨鍦ㄤ竴绉嶅彲鑳斤紝灏辨槸|x-1|=0涓(y+3)^2=0銆傛墍浠=1銆亂=-3 x-y=1-(-3)=4
绛旓細瑙ｏ細瑕佷娇|x-1|+(y+3)^2=0鎭掓垚绔嬶細鍙渶婊¤冻锛歺-1=0 y+3=0 鍗筹細x=1锛寉= -3 鎵浠ワ細1-xy-xy2=1-1*锛-3锛鈥1*锛-3)^2= -5 1-xy-xy2鐨勫涓-5
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绛旓細甯缁濆鍊鐨勬暟锛屾煇鏁扮殑骞虫柟鏄ぇ浜庣瓑浜0鐨 鏍瑰彿涓嬬殑鏁颁篃鏄ぇ浜庣瓑浜0鐨 鑻ヤ笁涓暟鍔犺捣鏉ョ瓑浜0鐨勮瘽锛岃繖涓変釜蹇呴』閮芥槸0 鎵浠x=1 y=-3 z=2
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绛旓細绠鍗曪紝x涓1鐨勭粷瀵瑰鏄ぇ浜庢垨鑰呯瓑浜0 (y鍗3)鐨勫钩鏂瑰ぇ浜庢垨鑰呯瓑浜0 x鍗亂鍗亃鐨勫钩鏂规牴澶т簬鎴栬呯瓑浜0 閭ｄ箞鍙湁涓涓彲鑳斤紝x涓1=0锛(y鍗3)=0锛寈鍗亂鍗亃=0 閭ｄ箞X=1锛孻=-3锛孼=2 X+Y-2=-4
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