sin2π-x=x吗? sin(2π+x)=?
sin(x+\u03c0/2)\u548csin(x-\u03c0/2)\u7684\u533a\u522b?\u600e\u4e48\u5224\u65ad\u5b83\u4eec\u7684\u6b63\u8d1f\u5462\uff1fsin(x-\u03c0/2)
=-sin(\u03c0/2-x)
=-cosxsin(x+\u03c0/2)=cosx\u4e00\u822c\u60c5\u51b5\u4e0b\u4e8c\u8005\u4e0d\u7b49\u3002
\u53ea\u6709\u5f53x=k\u03c0+\u03c0/2\u65f6\u76f8\u7b49\u3002
\u540c\u89d2\u4e09\u89d2\u51fd\u6570\u57fa\u672c\u5173\u7cfb\u5f0f\u4ecb\u7ecd
1\u3001\u5012\u6570\u5173\u7cfb\uff1atan\u03b1 \u00b7cot\u03b1=1\u3001sin\u03b1 \u00b7csc\u03b1=1\u3001cos\u03b1 \u00b7sec\u03b1=1\uff1b
2\u3001\u5546\u7684\u5173\u7cfb\uff1a sin\u03b1/cos\u03b1=tan\u03b1=sec\u03b1/csc\u03b1\u3001cos\u03b1/sin\u03b1=cot\u03b1=csc\u03b1/sec\u03b1\uff1b
3\u3001\u548c\u7684\u5173\u7cfb\uff1asin²\u03b1+cos²\u03b1=1\u30011+tan²\u03b1=sec²\u03b1\u30011+cot²\u03b1=csc²\u03b1\u3002
\u7b49\u4e8esinx\uff0c\u662f\u4e2a\u4ee52\u03c0\u4e3a\u5468\u671f\u7684\u5468\u671f\u51fd\u6570
解:sin2π-x ≠ xsin2π-x=0-x
=-x
sin2∏=0
sin2∏-x=-x
sin(2π-x)=sin(-x)=-sinx
绛旓細sin2蟺-x=0-x =-x
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