初二数学解方程，这两题怎么做？过程
\u521d\u4e8c\u6570\u5b66\u89e3\u65b9\u7a0b\uff0c\u8fd9\u4e24\u9898\u600e\u4e48\u505a\uff1f\u8fc7\u7a0b\u7b2c\u4e00\u9898\uff1a\u4ea4\u53c9\u76f8\u4e58 \u5373\uff1a7x=5(x-2)\u5373\u53ef\u7b97\u51fax\u7684\u503c\u3002\u3002\u3002\u3002\u7b2c\u4e8c\u9898\uff0c\u5c06\u51481\u8f6c\u5316\u6210x-1/x-1,,\u52192/x-1=x-1/x-1+1/x-1..
(1)解：两边乘(x+1)(x-1)(x+1)²-4=(x+1)(x-1)
x²+2x+1-4=x²-1
2x=2
x=1
经检验，x=1时公分母(x+1)(x-1)=0
是增根，舍去
（2）解：原式两边乘以（x-3）
化为：1+2（x-3）=x-4
即：2x-5=x-4
x=1
经检验，x=1时公分母（x-3）≠0
所以x=1是原方程的根
第一题通分，然后分母乘到右边，两边约掉x^2，化简成一元一次方程
第二题把右边移到左边，分子分母同时变号，化简为一元一次方程即可
1（x+1）的平方-4=x方-1；打开后可得出x=1 2 5-x/X-3=-2,除过去x=1
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