这道题f(0)=0是怎么来的。。 这道题f(0)=?怎么解啊
f\uff080-0\uff09\u4ec0\u4e48\u610f\u601d?\u662f\u600e\u4e48\u6765\u7684\u5462?f(0-0)\u8868\u793a\u57280\u8fd9\u4e00\u70b9 \u5de6\u8fb9\u7684\u6781\u9650
\u50cf f(x+0)\u8868\u793a\u5728x\u8fd9\u4e00\u70b9 \u53f3\u8fb9\u7684\u6781\u9650
\u50cf f(x-0)\u8868\u793a\u5728x\u8fd9\u4e00\u70b9 \u5de6\u8fb9\u8fb9\u7684\u6781\u9650
\u5982\u679c\u7b54\u6848\u5bf9\u60a8\u6709\u5e2e\u52a9\uff0c\u771f\u8bda\u5e0c\u671b\u60a8\u7684\u91c7\u7eb3\u548c\u597d\u8bc4\u54e6\uff01\uff01
\u795d\uff1a\u5b66\u4e60\u8fdb\u6b65\u54e6\uff01\uff01
*^_^* *^_^*
\u5b9a\u4e49 f(0) =2/3
f'(0+)
=lim(x->0) sin(2x)/(2x)
=2/3
lim(x->0-) f(x)
=lim(x->0-) (a+ sinx)
=a
=> a =2/3
因为 f(-x)=-f(x)，令x=0，则有f(0)=-f(0)，故f(0)=0
奇函数
f(-x)= - f(x)
令 x = 0 有
f(0)= - f(0)
2*f(0)= 0
故
f(0)= 0
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