已知弧长和拱高怎样求所在圆的半径 知道圆弧的弧长和拱高，怎么求半径
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Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=505
R1=479.915
R2=482.017
R3=482.034
R4=482.034
R=482.034\u6beb\u7c73
已知弧长为l，拱高h.
则有，
r·θ=l,
cosθ/2=（r-h）/r
求解方程组，可以解得r.
这里只是提供了方法，剩下部分请自行解答。
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