微积分之不定积分1题
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如图
2*(cosx)^2=(cos2x)-1
积分(cosx)^3dx=(cosx)^2dsinx
(cosx)^2+(sinx)^2=1
∫sin^2xdx+∫cos^3xdx
=∫(1-cos2x)/2dx+∫cos^2xdsinx
=x/2-(sin2x)/4+∫(1-sin^2x)dsinx
=x/2-(sin2x)/4+sinx+(sin^3x)3+C
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