画出y=sinx,x∈[0,2兀]和y=cosx,x∈[-二分之兀,二分之三兀]的简图 作函数y=2sinx，x属于[0，2兀]的图象
\u7531\u4e24\u66f2\u7ebfy=sinx\uff08x\u2208[0\uff0c2\u03c0]\uff09\u548cy=cosx\uff08x\u2208[0\uff0c2\u03c0]\uff09\u6240\u56f4\u6210\u7684\u5c01\u95ed\u56fe\u5f62\u7684\u9762\u79ef\u4e3a______\u7531y=sinx\uff08x\u2208[0\uff0c2\u03c0]\uff09\u548cy=cosx\uff08x\u2208[0\uff0c2\u03c0]\uff09\uff0c\u53ef\u5f97\u4ea4\u70b9\u5750\u6807\u4e3a\uff08\u03c04\uff0c22\uff09\uff0c\uff085\u03c04\uff0c22\uff09\uff0c\u2234\u7531\u4e24\u66f2\u7ebfy=sinx\uff08x\u2208[0\uff0c2\u03c0]\uff09\u548cy=cosx\uff08x\u2208[0\uff0c2\u03c0]\uff09\u6240\u56f4\u6210\u7684\u5c01\u95ed\u56fe\u5f62\u7684\u9762\u79ef\u4e3aS=\u222b\u03c040\uff08cosx-sinx\uff09dx+\u222b5\u03c04\u03c04\uff08sinx-cosx\uff09dx+\u222b2\u03c05\u03c04\uff08cosx-sinx\uff09dx=\uff08sinx+cosx\uff09|\u03c040-\uff08sinx+cosx\uff09|5\u03c04\u03c04+\uff08sinx+cosx\uff09|2\u03c05\u03c04=22\uff0e\u6545\u7b54\u6848\u4e3a\uff1a22<
\u4e0a\u56fe\u5373\u4e3ay=2sinx\uff0cx\u2208\u30100\uff0c2\u03c0\u3011\u7684\u56fe\u50cf
y=2sinx\u7684\u56fe\u50cf\u5177\u4f53\u505a\u6cd5\u4e3a\uff1a
\uff081\uff09\u753b\u51fa\u5e73\u9762\u76f4\u89d2\u6307\u6807\u7cfb\uff1b
\uff082\uff09\u5c06\u3010x\uff0c2\u03c0\u3011\u5206\u4e3a5\u4e2a\u7279\u6b8a\u70b9\uff0c\u5373x=0\uff0cx=\u03c0/2\uff0cx=\u03c0\uff0cx=3\u03c0/2\uff0cx=2\u03c0
\uff083\uff09\u5c06\u8fd9\u4e9bx\u503c\u4ee3\u5165\u51fd\u6570\u4e2d
\u5f53x=0\u65f6\uff0cy=2sin0=2\u00d70=0
\u5f53x=\u03c0/2\u65f6\uff0cy=2sin\u03c0/2=2\u00d71=2
\u5f53x=\u03c0\u65f6\uff0cy=2sin\u03c0=2\u00d70=0
\u5f53x=3\u03c0/2\u65f6\uff0cy=2sin3\u03c0/2=2\u00d7\uff08-1\uff09=-2
\u5f53x=2\u03c0\u65f6\uff0cy=2sin2\u03c0=2\u00d70=0
\uff084\uff09\u5c06\uff080\uff0c0\uff09\u3001\uff08\u03c0/2\uff0c2\uff09\u3001\uff08\u03c0\uff0c0\uff09\u3001\uff083\u03c0/2\uff0c-2\uff09\u3001\uff082\u03c0\uff0c0\uff09\u8fd9\u4e94\u70b9\u5728\u76f4\u89d2\u5750\u6807\u7cfb\u4e2d\u6807\u6ce8\u51fa\u6765\uff0c\u5e76\u5c06\u8fd9\u4e94\u70b9\u7528\u66f2\u7ebf\u8fde\u63a5\u8d77\u6765\u3002
红色的是sinx ，x∈[0,2π]区间的图像
黄色的是cosx，x∈[0,3π/2]区间的图像
望采纳！谢谢思密达^_^
绛旓細绾㈣壊鐨勬槸sinx 锛寈鈭圼0,2蟺]鍖洪棿鐨勫浘鍍 榛勮壊鐨勬槸cosx锛x鈭圼0,3蟺/2]鍖洪棿鐨勫浘鍍 鏈涢噰绾筹紒璋㈣阿鎬濆瘑杈綹_^
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绛旓細鍥炵瓟锛x=0,y=0 x=蟺/2,y=1 x=蟺,y=0 x=3蟺/2,y=1, x=2蟺,y=0
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