若等比数列{an}中,a3=3,a5=27,则此数列的公比为(  )A.3B.-3C.±3D.±

\u82e5\u7b49\u6bd4\u6570\u5217{an}\u4e2d\uff0ca3=3,a5=9,\u5219\u6b64\u6570\u5217\u7684\u516c\u6bd4\u4e3a\u591a\u5c11\uff1f

a5=a3q^2 a3=3,a5=9
\u6240\u4ee5q=\u221a3 (\u7531\u9898\u77e5\u9053a5>a3,\u6240\u4ee5\u6b64\u7b49\u6bd4\u6570\u5217\u662f\u9012\u589e\u6570\u5217\u3002\u6545\u820d\u53bb-\u221a3.\uff09
\u6240\u4ee5\u516c\u6bd4\u4e3a\u221a3

a1=1
a1*a2/a1*a3/a2*a4/a3*a5/a4=1^6*q^(1+2+3+4)
\u5373a5=1*q^10=(-\u221a2)^10=2^5=32
\u8fd9\u662f\u6211\u5728\u9759\u5fc3\u601d\u8003\u540e\u5f97\u51fa\u7684\u7ed3\u8bba\uff0c
\u5982\u679c\u80fd\u5e2e\u52a9\u5230\u60a8\uff0c\u5e0c\u671b\u60a8\u4e0d\u541d\u8d50\u6211\u4e00\u91c7\u7eb3~\uff08\u6ee1\u610f\u56de\u7b54\uff09
\u5982\u679c\u4e0d\u80fd\u8bf7\u8ffd\u95ee\uff0c\u6211\u4f1a\u5c3d\u5168\u529b\u5e2e\u60a8\u89e3\u51b3\u7684~
\u7b54\u9898\u4e0d\u6613\uff0c\u5982\u679c\u60a8\u6709\u6240\u4e0d\u6ee1\u613f\u610f\uff0c\u8bf7\u8c05\u89e3~

设等比数列{an}的公比为q,
由a3=3,a5=27,得q2
a5
a3
27
3
=9

∴q=±3.
故选C.

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