已知a是方程x的平方-2012x+1=0的一个根，试求a的平方-2011a+a的平方+1分之201 已知a是方程x平方减2017x加1等于0的一个根，求a平方减...
\u5df2\u77e5a\u662f\u65b9\u7a0bx\u7684\u5e73\u65b9-2011x+1=0\u7684\u4e00\u4e2a\u6839,\u6c42a\u7684\u5e73\u65b9-2012a+2011\u5206\u4e4ba\u7684\u5e73\u65b9+1\u7684\u503c???\u7531\u4e8ea\u662f\u65b9\u7a0bx^2-2011x+1=0\u7684\u4e00\u4e2a\u89e3\uff0c\u6240\u4ee5a^2-2011a+1=0,
\u90a3\u4e48a^2-2012a+a^2/2011+1=a^2-2011a-a+a^2/2011+1=(a^2-2011a+1)-a+a^2/2011=0+a^2/2011-a=a^2/2011-a=a^2/2011-2011a/2011+1/2011-1/2011=(a^2-2011a+1)/2011-1/2011=0/2011-1/2011
=-1/2011
\u6240\u4ee5\u503c\u4e3a-1/2011
a²-2017a+1=0
a²+1=2017a
a²-2016a+2017/(a²+1)
=a²-2017a+a+2017/(2017a)
=a-1+1/a
=(a²-a+1)/a
=(2017a-a)/a
=2016
∴a²=2012a-1
原式=2012a-1-2011a+2012/(2012a-1+1)
=a-1+1/a
=(a²+1)/a-1
=(2012a-1+1)/a-1
=2012-1
=2011
绛旓細=(a²+1)/a-1 =(2012a-1+1)/a-1 =2012-1 =2011
绛旓細=(a-1)+1/a =(a-1)-(a-2012)=2011
绛旓細=(a-1)+1/a =(a-1)-(a-2012)=2011
绛旓細宸茬煡a,b鏄竴鍏冧簩娆鏂圭▼x鐨勫钩鏂-2x-1=0鐨勪袱涓疄鏁版牴,鍒欎唬鏁板紡(a-b)(a+b-2)+ab 宸茬煡a,b鏄竴鍏冧簩娆℃柟绋媥鐨勫钩鏂-2x-1=0鐨勪袱涓疄鏁版牴,鍒欎唬鏁板紡(a-b)(a+b-2)+ab鐨勫肩瓑浜... 宸茬煡a,b鏄竴鍏冧簩娆℃柟绋媥鐨勫钩鏂-2x-1=0鐨勪袱涓疄鏁版牴,鍒欎唬鏁板紡(a-b)(a+b-2)+ab鐨勫肩瓑浜 灞曞紑 鎴戞潵...
绛旓細鍥犱负a鏄柟绋媥鐨勫钩鏂-2013x+1绛変簬0鐨勪竴涓牴 鎵浠^2-2013a+1=0锛屾墍浠^2-2012a=a-1 a^2+1=2013a,浠ｄ汉锛屽緱锛宎鐨勫钩鏂-2012a+锛坅鐨勫钩鏂+1鍒嗕箣2013)=a^2-2012a+2013/(a^2+1)=a-1+2013/2013a =a-1+1/a =a+(1/a)-1 灏哸^2-2013a+1=0涓よ竟鍚岄櫎浠,寰楋紝a-2013+1/a=...
绛旓細a鏄柟绋媥^2-2013x+1=0鐨勪竴涓牴,鈭碼^2=2013a-1,鈭碼^2-2012a+2013/(a^2+1)=a-1+2013/2013a =(a^2+1)/a-1 =2013-1 =2012.
绛旓細鈭a鏄涓鍏冧簩娆鏂圭▼x鐨勫钩鏂-2014x+1=0鐨勮В 鈭碼²-2014a+1=0 鈭碼²+1=2014a 鈭碼²-2013a+2014/(a²+1)=a²-2013a+2014/(2014a)=a²-2013a+1/a =a-1+1/a =(a²-a+1)/a =2013a/a =2013 ...
绛旓細鐢遍鎰忓緱锛宎骞虫柟-2013a+1=0锛屽垽鍒紡锛0.淇╄竟鍚岄櫎浠锛屽緱a+a鍒嗕箣1=2013.鍙堟湁锛a骞虫柟-2013a=-1锛屾墍姹傚紡瀛=a+a鍒嗕箣1=2013
绛旓細a鏄柟绋媥^2-2013x+1=0"鐨勪竴涓牴 a^2-2013a+1=0 鎵浠 a^2=2013a-1 a^2+1=2013a 鎵浠^2-2012a+2013/(a^+1)=2013a-1+2012a+2013/(2013a)=a-1+1/a=(a^2-a+1)/a=(2012a)/a=2012
绛旓細杩欐槸涓绉嶅緢甯歌鐨勯鍨嬶紝鍒╃敤宸茬煡鐨鏉′欢锛屽湪鏈煡鐨勯棶棰橀噷鎷煎噾鍑虹被浼间簬宸茬煡鏉′欢鐨勫紡瀛愶紝鐒跺悗鍐嶈繘琛屾眰瑙ｃ1銆佹棦鐒a鏄痻²-2010x+1 =0鐨勬牴锛岄偅涔堟弧瓒砤²-2010a+1 =0 2銆佹湭鐭²-2009a+2010/(a²+1锛= a²-2010a+1+a-1+2010/2010a = 0 + a -1 + (1/a)= (...
