高数求极限。再附上草稿详解，求大神发威。 高数求极限，答案附在题目后面了，谢谢了
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WiFi下或开启原图后观看。我就这么轻松收下了50大洋？？
绛旓細e^(1/6)鎴戠殑杩囩▼鏄埄鐢ㄦ礇蹇呰揪娉曞垯銆傝繃绋嬪涓嬪浘锛
绛旓細f(x)=x^3-x^2-x+1 f(-1)=0 x^3-x^2-x+1=(x+1)(x^2+ax+1)coef. of x 1+a =-1 a=-2 x^3-x^2-x+1 =(x+1)(x^2-2x+1)=(x+1)(x-1)^2 g(1) =2x^3-3x^2 +1 =0 2x^3-3x^2 +1 =(x-1)(2x^2+bx-1)coef. of x -1-b=0 b=-1 2x^3-3...
绛旓細1銆佸叧浜楂樻暟姹傛瀬闄闂瑙佷笂鍥俱2銆佽繖涓珮鏁扮涓棰樻眰鏋侀檺锛岀敤绗簩涓噸瑕佹瀬闄愬彲浠ユ眰鍑恒3銆佺浜岄姹傛瀬闄愶紝0浠ｅ叆鍚庯紝鏋侀檺鍙互姹傚嚭銆4銆佺鍥涢姹傛瀬闄愶紝鐢ㄧ涓涓噸瑕佹瀬闄愬彲浠ユ眰鍑恒傛垨绛変环鏃犵┓灏忎唬鎹5銆佺浜旈姹傛瀬闄愶紝鍏堝垎瑙ｅ洜寮忓拰鍖栫畝鍚庯紝鏋侀檺鍙互姹傚嚭銆
绛旓細lim e^[4n^2ln(cos1/n)] 鍐嶇敤涓婇鐨勬柟娉曞氨鍙互浜 鏋侀檺涓篹^(-2)褰搙鈫0鏃讹紝ln锛1+x锛夆啋x 杩欎竴鏃犵┓灏忔浛鎹㈤渶瑕佺墷鐗㈡帉鎻° x鍙互鏄竴涓〃杈惧紡銆傚笇鏈涘浣犳湁鎵甯姪锛屾湜閲囩撼銆
绛旓細lim(x->1)[x/(x-1)-1/lnx]=lim(x->1)[(xlnx-(x-1))/(x-1)lnx]=lim(x->1)[(xlnx-x+1)/(xlnx-lnx)]=lim(x->1)[((lnx+1)-1)/(lnx+1)-1/x]鈫愭礇蹇呰揪娉曞垯 =lim(x->1){lnx/[(xlnx+x-1)/x]} =lim(x->1)[xlnx/(xlnx+x-1)]=lim(x->1)[(lnx+1)...
绛旓細1銆佹ゼ涓 鐨勮繖鍥涢亾棰橈紝鍒嗗埆瑙ｇ瓟鍦ㄤ笅闈㈢殑鍥涘紶鍥剧墖涓婏紝姣忛亾棰樼殑瑙ｇ瓟鏂规硶锛岄兘鍏蜂綋鏍囩ず鍦ㄥ悇棰樼洰鐨勪笂鏂癸紱姣忓紶鍥剧墖閮藉彲鐐瑰嚮鏀惧ぇ锛屾斁澶у悗鐨勫浘鐗囨洿鍔犳竻鏅般.2銆佸寰Н鍒嗭紝瀛︾殑鏄柟娉曘備腑瀛︾敓鐨勯偅绉嶆璁扮‖鑳屻佸洬鍥靛悶鏋ｃ佹椿鍓ョ敓鍚炵殑姝诲鍏紡鏂规硶瑕佺粷瀵规垝缁濓紒閭ｆ槸鑴戞畫鐨勫娓ｈ涓猴紝澶у鐢熶竴瀹氳鏈夋濇兂鎵嶈锛.3銆...
绛旓細2014-10-31 楂樻暟,鍒ゆ柇濂囧伓鎬,姹傛瀬闄,绗笁棰樺拰绾㈢瑪鎵撻挬鐨勯,姹傝瑙,鎵嬪啓... 2016-01-12 澶т竴楂樻暟,閲嶈鏋侀檺鐨勫簲鐢,棰樼洰濡傚浘,姹傝瑙 2020-03-13 楂樻暟姹傛瀬闄,棰樼洰濡傚浘,姹傝瑙 2019-10-16 澶т竴楂樻暟棰,棰樼洰濡傚浘,姹傚叾鏋侀檺,闇瑕佽繃绋,姹傚ぇ绁炶В绛 2 2014-11-13 楂樻暟,澶归煎噯鍒欐眰鏋侀檺,姹傛瑙ｈ瑙,鍐欏湪绾镐笂...
绛旓細澶氬厓鍑芥暟鏋侀檺鐨勬眰娉曠被浼间竴鍏冨嚱鏁姹傛瀬闄銆傜(1)銆(2)鍙互鐩存帴浠ｅ叆姹傚嚭鏋侀檺锛岀(3)銆(4)銆(5)銆(6)鍙互浠跨収涓鍏冨嚱鏁版眰鏋侀檺涓父鐢ㄧ殑绛変环鏃犵┓灏忚繘琛屼唬鎹備互绗(3)棰樹负渚嬶紝鍙互鐢▁瓒嬩簬0鏃垛垰(1锛媥)锛1锝瀤/2锛岃繖閲屼笉杩囨槸灏嗏渪鈥濇崲鎴愪簡xy锛屽墿涓嬬殑涔熸槸濡傛銆
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