标准状况下将224lhcl溶于一升水中
224L=10mol=365g质量分数=365/（365+1000）=26.7%.溶液质量=1365g,体积=1365/1.1=1.241L,浓度=10/1.241=8.06mol/L
绛旓細224L梅22.4L/mol=10mol 1000mL=1L 10mol梅1L=10mol/L
绛旓細n=224/22.4=10mol 婧舵恫浣撶Н涓篤 V=m梅瀵嗗害 m=婧惰川+婧跺墏=10*36.5+635*1.0=1000g c=n/V=10梅[锛1000梅1.18锛*10^-3]=11.8mol/L 鐢ㄥ瘑搴︾畻鍑烘潵鐨勪綋绉崟浣嶆槸ml 鎹㈢畻鎴怢 鎵浠ヤ箻浠10^-3
绛旓細224L=10mol=365g璐ㄩ噺鍒嗘暟=365/锛365+1000锛=26.7%.婧舵恫璐ㄩ噺=1365g,浣撶Н=1365/1.1=1.241L,娴撳害=10/1.241=8.06mol/L
绛旓細HCl鐨勭墿璐ㄧ殑閲=224/22.4=10mol HCl鐨勮川閲=10*36.5=365鍏 婧舵恫鐨勮川閲365+835=1200鍏 婧舵恫鐨勪綋绉=1200/1.2=1000cm3=1L 鎵寰楃洂閰哥殑鐗╄川鐨勯噺娴撳害涓篲_10/1=10mol/L___.
绛旓細锛1锛鏍囧噯鐘跺喌涓锛224L姘寲姘鐨勭墿璐ㄧ殑閲忔槸224L梅22.4L/mol锛10mol鎵浠ユ隘鍖栨阿鐨勮川閲忔槸10mol脳36.5g/mol锛365g婧跺墏姘寸殑璐ㄩ噺鏄635g鍥犳婧舵恫鐨勮川閲忔槸635锛365g锛1000g鎵浠ヨ鐩愰吀涓憾璐ㄧ殑璐ㄩ噺鍒嗘暟鏄 锛2锛夋牴鎹 鍙煡璇ョ洂閰哥殑娴撳害鏄 銆傦紙3锛夌敱浜庡湪绋閲婅繃绋嬩腑锛屾憾璐ㄦ槸涓嶅彉鐨勶紝鎵浠ョ█閲婄殑鍚庣殑婧舵恫...
绛旓細姘寲姘鐗╄川鐨勯噺涓10mol锛10脳36.5=365鍏 鎬昏川閲忎负1365鍏嬶紝瀵嗗害1.32鍏嬫瘡绔嬫柟鍘樼背銆備綋绉1365/1.32=1034.09ml 鐗╄川鐨勯噺娴撳害涓9.67mol/L
绛旓細1.224HCL鍗10molHCl m(HCl)=10mol*36.5g/mol=365g 婧舵恫鎬昏川閲365g+635g=1000g 鍗847.46mL=0.84746L C(HCL)==10mol/0.84746L=11.8mol/L 鎵浠婧朵簬姘存憾娑茬墿璐ㄧ殑閲忔祿搴︿负11.8mol/L 10.0ml涓湁HCl 0.118mol C(绋閲)=0.118mol/1.45L=0.0813mol/L 2.纰抽吀閽犵墿璐ㄧ殑閲忎负0.0026...
绛旓細锛1锛12.0 mol路 L -1 锛2锛26.9 L33.6 g 锛1锛塶(HCl)="224" L/22.4 L路 mol -1 ="10.0" molm(HCl婧娑)="635" g+10.0 mol脳36.5 g路 mol -1 =1.00脳10 3 gc(HCl)= =" 12.0 " mol 路 L -1 锛2锛塇Cl+NaHCO 3 ===NaCl+H 2 O+CO 2 鈫1 mol ...
绛旓細HCl鐨勭墿璐ㄧ殑閲 224/22.4=10(mol)HCl鐨勮川閲10*36.5锛365锛坓锛夋憾娑茬殑璐ㄩ噺365+635*1锛1000锛坓锛塇Cl鐨勮川閲忓垎鏁365/1000脳100锛咃紳36.5锛 c锛圚Cl锛夛紳1000*1.19*36.5%/36.5=11.9(mo/L)绋閲婂悗娴撳害 11.9*10锛1190c 锛宑锛0.1锛坢ol/L锛
绛旓細n(hcl)=10mol C(hcl)=11.8mol/L v(娑)=[(635g+10molx36.5g/mol)x10^-3L/mL]/1.18g/mol=0.85L C(hcl)=11.8mol/L C(hcl绋)=n/v=[C(hcl)x10x10^-3L/ml]/1.45L=0.08mol/L 鑷繁鍋氱殑锛岀瓟妗堝簲璇ユ槸瀵圭殑銆傛墦寰楃湡绱晩銆
