已知R1=R2=R3=R4=R5=1欧姆,请计算A.B点间的等效电阻Rab等于多少? 计算图1电路中a、b两端的等效电阻Rab,有具体步骤吗?谢谢...

\u5df2\u77e5R1=R2=R3=3\u03a9\uff0cR4=R5=6\u03a9\uff0c\u8bd5\u6c42\u56fe\u4e2d\u7684\u7b49\u6548\u7535\u963bRab

Rab = 7\u03a9
\u7535\u8def\u4eff\u771f\u7ed3\u679c\u5982\u4e0b\u56fe\uff1aRab = 7V / 1A = 7\u03a9

\u7535\u8def\u5206\u6790\u5982\u4e0b\uff1a
1\uff0c\u9996\u5148R4 \u88ab\u53f3\u8fb9\u7684\u7ebf\u8def\u7ed9\u77ed\u8def\u4e86\uff0c\u90a3\u4e48\u628aR4 \u6362\u6210\u5bfc\u7ebf\uff0c\u7535\u8def\u5c31\u53d8\u5982\u4e0b\u4e86\uff1a

2\uff0c \u518d\u628a\u7535\u8def\u7b80\u5316\u4e0b\uff0c\u540c\u7535\u4f4d\u7684\u8fde\u6210\u4e00\u70b9\uff1a

3\uff0c\u8fd9\u6837\u7535\u8def\u5c31\u5f88\u6e05\u6670\u4e86\uff0cRab = \uff08R1//R2//R3) + R5 = 1+ 6 = 7\u03a9
\u53ef\u4ee5\u5173\u6ce8\u4e0b\u6211\u7684\u516c\u4f17\u53f7\uff1a\u5c0f\u563f\u4f83\u7535\u5b50\uff0c\u5e73\u65f6\u6211\u4f1a\u5206\u4eab\u7535\u8def\u8bbe\u8ba1\u7684\u77e5\u8bc6\u3002

\u8fd9\u79cd\u7b80\u5355\u7684\u7535\u8def\uff0c\u53ea\u8981\u91cd\u65b0\u753b\u4e00\u4e0b\uff0c\u5c31\u53ef\u4ee5\u660e\u767d\u5404\u7535\u963b\u4e4b\u95f4\u7684\u5173\u7cfb\u4e86\u3002
\u4e0a\u8ff0\u7535\u8def\u4e2d\uff0cab\u4e24\u70b9\u4e4b\u95f4\u63a5\u670910\u03a9\u7535\u963b\uff0c\u540c\u65f6\u4e24\u4e2a6\u03a9\u7535\u963b\u5e76\u8054\u4e4b\u540e\u518d\u4e0e7\u03a9\u7535\u963b\u4e32\u8054\uff0c\u4e5f\u63a5\u5728ab\u4e4b\u95f4\u3002\u6240\u4ee5\uff0cab\u4e4b\u95f4\u7684\u7535\u963bRab\u5c31\u662f10\u03a9\u7535\u963b\u4e0e\u4e24\u5916\u4e00\u4e2a\u7ec4\u5408\u7535\u963b\u7684\u5e76\u8054\uff0c\u8fd9\u4e2a\u7ec4\u5408\u7535\u963b\u662f\u7531\u4e24\u4e2a6\u03a9\u7535\u963b\u5e76\u8054\u540e\u518d\u4e0e7\u03a9\u7535\u963b\u4e32\u8054\u540e\u5f97\u5230\u7684\u3002
Rab = 10//(6//6+7)
= 10//(3+7)
= 10//10
= 5 (\u03a9)
\u5373\uff0c\u56fe\u4e00\u7535\u8def\u4e2d\uff0cab\u4e24\u7aef\u7684\u7b49\u6548\u7535\u963bRab\u7b49\u4e8e5\u6b27\u59c6\u3002

本题的等效电路图如下:

由图可知:R3,R4串联,则R3 +   R4   =2 欧姆,它和R5并联得2/3欧姆,然后,这个电阻再和R2串联,得到的电阻是5/3欧姆,  最后,相当于5/3欧姆的电阻和R1并联。所以Rab=5/8欧姆。



等效电阻等于R3串R4并R5后串R2后再与R1并联的值5/8

R3+R4=2欧 并R5后为2/3欧,串R2后为5/3欧,再并上R1等于5/8欧

上图的等效电路如下:





等效电阻:Rab=R1//(R2+R5//(R3+R4))=5/8欧。

Rab=1.4欧

  • 鐗╃悊鐨勭數璺濡傚浘,宸茬煡R1=R2=R3=R4=R,鍒橝F涓ょ鐨勭數闃讳负 缁欎釜鏈夎绠楃殑...
    绛旓細R2鍜R3鍜R4骞惰仈锛屽啀鍜R1涓茶仈 R鎬=R/3+R=4R/3
  • R1=R2=R3=R4=R5=R6=R7=R8=R9=R10=3惟,姹傜瓑鏁堢數闃?(璇︾粏...
    绛旓細1銆R1銆丷2涓茶仈鐨勬荤數闃绘槸 Ra=R1+R2=3+3=6娆с2銆丷a涓R3骞惰仈鐨勬荤數闃绘槸 Rb=Ra*R3 /(Ra+R3)=6*3 /(6+3)=2娆 銆3銆佸悓鐞,R4銆丷5涓茶仈鐨勬荤數闃绘槸6娆,瀹冨啀涓嶳6骞惰仈鐨勬荤數闃绘槸 Rc=2娆(杩囩▼涓庡墠浜屾鐩稿悓)銆4銆丷b...
  • 宸茬煡R1=R2=R3=R4=R5=1娆у,璇疯绠桝.B鐐归棿鐨勭瓑鏁堢數闃籖ab绛変簬澶氬皯?_鐧惧害...
    绛旓細鐢卞浘鍙煡锛R3锛孯4涓茶仈锛屽垯R3 + R4 =2 娆у锛屽畠鍜孯5骞惰仈寰2/3娆у锛岀劧鍚庯紝杩欎釜鐢甸樆鍐嶅拰R2涓茶仈锛屽緱鍒扮殑鐢甸樆鏄5/3娆у锛 鏈鍚庯紝鐩稿綋浜5/3娆у鐨勭數闃诲拰R1骞惰仈銆傛墍浠ab=5/8娆у銆
  • 濡傚浘,宸茬煡R1=R2=R3=R4=R5=R6=R7=10惟姹侫B闂寸殑绛夋晥鐢甸樆Rab绛変簬澶氬皯...
    绛旓細A涓嶳1涔嬮棿鏍嘪.R4 ,R5 涔嬮棿鏍嘪.涓ょ偣涓哄悓涓鐐 B浜 R7 涔嬮棿鏍嘫.R3,R4涔嬮棿鏍嘫.涓ょ偣涓哄悓涓鐐.鐢甸樆涓よ竟缁忚繃X,Y鐐(姝h礋鏋)鐨勫彧鏈塕1鍜孯4 涓ょ數闃诲苟鑱.R鎬=R1*R2/(R1+R2)=5娆 ...
  • 鐢佃矾濡傚浘,R1=R2=R3=R4=R=10娆у,绗竴闂綋寮鍏砈闂悎鏃,鐢佃矾绛夋晥鐢甸樆_鐧惧害...
    绛旓細娆у锛塕12锛漅1/2锛10/2锛5锛堟濮嗭級鍒欑瓑鏁堢數闃籖锛漅12*R34/锛圧12+R34锛夛紳20*5/锛20+5锛夛紳4锛堟濮嗭級锛2锛夊綋寮鍏硈闂悎鏃 鐢甸樆R1銆R2鍜R4骞惰仈锛岃孯3琚煭鎺 鎵浠ョ瓑鏁堢數闃籖锛漅1/3锛10/3锛3.3锛堟濮嗭級
  • 璁$畻涓嬪浘鎵绀虹數璺殑绛夋晥鐢甸樆.R1=R2=R3=R4=R.鍒楀嚭璁$畻杩囩▼.
    绛旓細浠栦滑鐨勪氦鐐瑰彧瑕佸湪杩欐牴绾夸笂閮芥槸鍙互鐨 涓鐩寸Щ鍔ㄥ埌R4宸﹁竟鐨勮繖鏍圭洿瑙掑 鎵浠ュ悓鐞嗘垜浠Щ鍔R3鐨勪笌R4鐨勪氦鐐 鎵浠ュ氨寰堝鐪嬪嚭鏉 R1銆丷3骞惰仈 R2銆丷4骞惰仈 鍥犳绛夋晥鐢甸樆灏辨槸銆愶紙R1*R3/(R1+R3)+锛圧1*R3/(R1+R3)锛夈=R ...
  • 宸茬煡鐢甸樆鐢佃矾濡傚浘鎵绀,R1=R2=R3=R4=R5=R6=1惟,鍒嗗埆姹侫B绔拰CB绔瓑鏁堢數 ...
    绛旓細1,1涓插緱2 2锛1骞跺緱2/3 2/3锛1涓插緱5/3 5/3,1骞跺緱锛(5/3)/(1+5/3)=5/8 5/8锛1涓插緱锛13/8 鎵浠AB=13/8娆
  • r1=R2=R3=R4=R5=4娆у,Uab绛変簬20浼,姹傜數娴佽〃涓庣數鍘嬭〃绀烘暟
    绛旓細杩欐牱娴佽繃R3鐨勭數娴佸氨鏄8/4=2A锛屽浘涓數娴佽〃鐨勬寚绀哄簲涓2A銆備粠R1 娴佽繃鏉ョ殑3A鐢垫祦鍒嗕袱璺紝鍥犳娴佽繃R2,R4鐨勭數娴佸氨鏄1A.杩欎釜鐢垫祦鍦≧2涓婄殑闄嶈惤鏄1*4=4浼.鍥句腑鐢靛帇琛ㄧ殑鎸囩ず搴斾负12+4=16浼忋傜瓟锛氬浘涓數娴佽〃鐨勬寚绀轰负2A銆
  • 宸茬煡R1=R2=R3=R4=R5=1Ω,姹俁AB
    绛旓細RAB=R5鈭(R1+R2鈭(R3+R4))=1鈭(1+1鈭2)=1鈭(1+2/3)=5/3梅(1+5/3)=5/8惟 鎮ㄥソ锛屽緢楂樺叴涓烘偍瑙g瓟锛宻kyhunter002涓烘偍绛旂枒瑙f儜 濡傛灉鏈鏈変粈涔堜笉鏄庣櫧鍙互杩介棶锛屽鏋滄弧鎰忚寰楅噰绾 濡傛灉鏈夊叾浠栭棶棰樿閲囩撼鏈鍚...
  • 宸茬煡R1=R2=R3=R4=R5=R,鐢垫睜鐢靛帇涓簎0,鍦ㄧ悊鎯崇姸鎬佷笅,姹傛瘡涓數闃荤殑鐢垫祦...
    绛旓細鐢垫祦R1=R2=R4=R5=U0/2R R3=0
  • 扩展阅读:求解方程计算器 ... 题图所示电路中已知r1=r2=r4 ... 万能计算器 ... 已知路由器r1的路由表如下 ... 方程计算器 ... 平方计算器在线计算 ... 空调r32氟换成r22氟行吗 ... 34-9分解算式 ... r1加r2加r3怎么算 ...

    本站交流只代表网友个人观点,与本站立场无关
    欢迎反馈与建议,请联系电邮
    2024© 车视网