已知R1＝R2＝R3＝R4＝R5＝1Ω，求RAB 如图所示电路等效电阻，其中R1=R2=R3=R4=R5=3欧...
\u5df2\u77e5R1=2\u03a9\u3001R2=3\u03a9\u3001R3=9\u03a9\u3001R4=6\u03a9\uff0c\u6c42\u56fe\u4e2d\u7535\u8def\u7684\u7b49\u6548\u7535\u963bRAB\uff1f\u89e3\u7b54\u5982\u4e0b\u3002
4\u6b27 \uff0c\u56fe\u7247\u5ba1\u6838\u4e2d
=1∥(1+1∥2)
=1∥(1+2/3)
=5/3÷(1+5/3)
=5/8Ω
您好，很高兴为您解答，skyhunter002为您答疑解惑
如果本题有什么不明白可以追问，如果满意记得采纳
如果有其他问题请采纳本题后另发点击向我求助，答题不易，请谅解，谢谢。
祝学习进步
绛旓細R2鍜R3鍜R4骞惰仈锛屽啀鍜R1涓茶仈 R鎬=R/3+R=4R/3
绛旓細1銆R1銆丷2涓茶仈鐨勬荤數闃绘槸 Ra=R1+R2=3+3=6娆с2銆丷a涓R3骞惰仈鐨勬荤數闃绘槸 Rb=Ra*R3 /(Ra+R3)=6*3 /(6+3)=2娆 銆3銆佸悓鐞,R4銆丷5涓茶仈鐨勬荤數闃绘槸6娆,瀹冨啀涓嶳6骞惰仈鐨勬荤數闃绘槸 Rc=2娆(杩囩▼涓庡墠浜屾鐩稿悓)銆4銆丷b涓嶳c涓茶仈鐨勬荤數闃绘槸 Rd=Rb+Rc=2+2=4娆 銆5銆丷8銆丷9骞惰仈鐨勬荤數闃绘槸 Re=...
绛旓細鎶婁粬鐨勭數璺浘绠鍖栦竴涓 浣犳妸R2涓婇潰鐨勮繛鎺ュ埌R1鐨勪氦鐐瑰線涓嬬Щ鍔 浠栦滑鐨勪氦鐐瑰彧瑕佸湪杩欐牴绾夸笂閮芥槸鍙互鐨 涓鐩寸Щ鍔ㄥ埌R4宸﹁竟鐨勮繖鏍圭洿瑙掑 鎵浠ュ悓鐞嗘垜浠Щ鍔R3鐨勪笌R4鐨勪氦鐐 鎵浠ュ氨寰堝鐪嬪嚭鏉 R1銆丷3骞惰仈 R2銆丷4骞惰仈 鍥犳绛夋晥鐢甸樆灏辨槸銆愶紙R1*R3/(R1+R3)+锛圧1*R3/(R1+R3)锛夈=R ...
绛旓細鐢卞浘鍙煡锛R3锛孯4涓茶仈锛屽垯R3 + R4 =2 娆у锛屽畠鍜孯5骞惰仈寰2/3娆у锛岀劧鍚庯紝杩欎釜鐢甸樆鍐嶅拰R2涓茶仈锛屽緱鍒扮殑鐢甸樆鏄5/3娆у锛 鏈鍚庯紝鐩稿綋浜5/3娆у鐨勭數闃诲拰R1骞惰仈銆傛墍浠ab=5/8娆у銆
绛旓細A涓嶳1涔嬮棿鏍嘪.R4 ,R5 涔嬮棿鏍嘪.涓ょ偣涓哄悓涓鐐 B浜 R7 涔嬮棿鏍嘫.R3,R4涔嬮棿鏍嘫.涓ょ偣涓哄悓涓鐐.鐢甸樆涓よ竟缁忚繃X,Y鐐(姝ｈ礋鏋)鐨勫彧鏈塕1鍜孯4 涓ょ數闃诲苟鑱.R鎬=R1*R2/(R1+R2)=5娆
绛旓細1锛夊綋寮鍏硈鏂紑鏃 鐢甸樆R1鍜R2骞惰仈锛岀數闃籖3鍜孯4涓茶仈鍚庡啀涓嶳2骞惰仈锛屾墍浠34锛漅3+R4锛20锛堟濮嗭級R12锛漅1/2锛10/2锛5锛堟濮嗭級鍒欑瓑鏁堢數闃籖锛漅12*R34/锛圧12+R34锛夛紳20*5/锛20+5锛夛紳4锛堟濮嗭級锛2锛夊綋寮鍏硈闂悎鏃 鐢甸樆R1銆丷2鍜孯4骞惰仈锛岃孯3琚煭鎺 鎵浠ョ瓑鏁堢數闃籖锛漅1/3锛10/3锛3.3锛堟濮嗭級
绛旓細1,1涓插緱2 2锛1骞跺緱2/3 2/3锛1涓插緱5/3 5/3,1骞跺緱锛(5/3)/(1+5/3)=5/8 5/8锛1涓插緱锛13/8 鎵浠AB=13/8娆
绛旓細RAB=R5鈭(R1+R2鈭(R3+R4))=1鈭(1+1鈭2)=1鈭(1+2/3)=5/3梅(1+5/3)=5/8惟 鎮ㄥソ锛屽緢楂樺叴涓烘偍瑙ｇ瓟锛宻kyhunter002涓烘偍绛旂枒瑙ｆ儜 濡傛灉鏈鏈変粈涔堜笉鏄庣櫧鍙互杩介棶锛屽鏋滄弧鎰忚寰楅噰绾 濡傛灉鏈夊叾浠栭棶棰樿閲囩撼鏈鍚庡彟鍙戠偣鍑诲悜鎴戞眰鍔╋紝绛旈涓嶆槗锛岃璋呰В锛岃阿璋傜瀛︿範杩涙 ...
绛旓細鐢垫祦R1=R2=R4=R5=U0/2R R3=0
绛旓細鐢垫祦鏄0.9A锛岃鐢佃矾绛夋晥涓R123骞惰仈鐒跺悗鍜R4涓茶仈锛孉1鏄R23鐨勭數娴侊紝A2鏄疪12鐨勭數娴
