sin(2π+x)=？ 为什么sin(2nπ+π/2)是等于1？

sin(2\u03c0+\u03b1)=\u591a\u5c11

sin(2\u03c0+\u03b1\uff09=sin\u03b1\uff0csin(2\u03c0-\u03b1\uff09=-sin\u03b1\uff0csin(3\u03c0-\u03b1\uff09=sin\u03b1\uff0csin(3\u03c0+\u03b1\uff09=-sin\u03b1\u3002\u5206\u6790\u8fc7\u7a0b\u5982\u4e0b\uff1a
2\u03c0\u5c31\u662f360\u5ea6\uff0c\u521a\u597d\u4e00\u5708\uff0c\u6240\u4ee5\u89d2\u5ea6\u4e00\u4e2a\u6837\uff0c\u5f97\u5230sin(2\u03c0+\u03b1)=sin\u03b1\u3002
sin(\u03c0-\u03b1\uff09=sin(\u03b1\uff09\uff0c(\u03c0+\u03b1\uff09\u662f\u8f6c\u4e86180\u5ea6\uff0c\u6240\u4ee5\u5c31\u6709sin(\u03c0+\u03b1\uff09=-sin\u03b1\u3002
sin(2\u03c0-\u03b1\uff09=sin(-\u03b1\uff09=-sin\u03b1\uff0c
sin(3\u03c0-\u03b1\uff09=sin(2\u03c0+\u03c0-\u03b1\uff09=sin(\u03c0-\u03b1\uff09=sin(\u03b1\uff09
sin(3\u03c0+\u03b1\uff09=sin(2\u03c0+\u03c0+\u03b1\uff09=sin(\u03c0+\u03b1\uff09=-sin(\u03b1\uff09
\u6269\u5c55\u8d44\u6599\uff1a
\u03c0/2\u00b1\u03b1\u4e0e\u03b1\u7684\u4e09\u89d2\u51fd\u6570\u503c\u4e4b\u95f4\u7684\u5173\u7cfb\uff1a
sin(\u03c0/2+\u03b1)=cos\u03b1
sin(\u03c0/2\uff0d\u03b1)=cos\u03b1
cos(\u03c0/2+\u03b1)=\uff0dsin\u03b1
cos(\u03c0/2\uff0d\u03b1)=sin\u03b1
tan(\u03c0/2+\u03b1)=\uff0dcot\u03b1
tan(\u03c0/2\uff0d\u03b1)=cot\u03b1
cot(\u03c0/2+\u03b1)=\uff0dtan\u03b1
cot(\u03c0/2\uff0d\u03b1)=tan\u03b1
\u03c0-\u03b1\u4e0e\u03b1\u7684\u4e09\u89d2\u51fd\u6570\u503c\u4e4b\u95f4\u7684\u5173\u7cfb\uff1a
cos(\u03c0\uff0d\u03b1)=\uff0dcos\u03b1
tan(\u03c0\uff0d\u03b1)=\uff0dtan\u03b1
cot(\u03c0\uff0d\u03b1)=\uff0dcot\u03b1

\u8fd9\u6837 \u5176\u5b9e\u5468\u671f\u51fd\u6570\u76f4\u63a5\u5c31\u80fd\u53bb\u63892\u03c0x

等于sinx，是个以2π为周期的周期函数

sin(2π+x)=sinx

sin(2π+x)=sinx

sinx

sin(2π+x)
=sinx

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sin(2蟺+x)=?
绛旓細绛変簬sinx锛屾槸涓互2蟺涓哄懆鏈熺殑鍛ㄦ湡鍑芥暟

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绛旓細y=2sin(蟺x)鍦ㄥ尯闂碵锛2锛4]涓婄殑鍥惧儚锛岄噰鐢ㄥ彇鐐规硶鏉ヨВ鍐炽傝繖涓嚱鏁扮殑鍛ㄦ湡鏄疶=2锛屽彲浠ュ厛浣滃嚭[0锛2]涓婂浘鍍忥紝鐒跺悗鍐嶄綔鍑哄叏鍥惧浘鍍忋

扩展阅读：tan2π ... π arcsiny ... arctan-1 ... sin（π+x） ... 简便计算器 ... sin 2派 x ... 求解方程计算器 ... 1-cosx ... 万能计算器 ...