x在0到正无穷,求x*e^(-x/y)在该范围的微积分
\u5fae\u79ef\u5206\u95ee\u9898\uff0c\u6b64\u9898X\u7684\u8303\u56f4\u4e3a\u4ec0\u4e48\u662f0\u52301\uff1f\u79ef\u5206\u533a\u57df\u4e3a
0\u2264\u03b8\u2264\u03c0/2
0\u2264r\u2264cos\u03b8
r=cos\u03b8\u8868\u793a\u5706
x^2+y^2=x
\u6240\u4ee5\uff0cD\u8868\u793a\u4e0a\u534a\u5706\uff0c
\u4e0a\u534a\u5706\u8868\u793a\u6210\u76f4\u89d2\u5750\u6807\uff0c\u5c31\u662f
0\u2264x\u22641
0\u2264y\u2264\u221a(x-x^2)
\u89e3\uff1a
\u222b(x-e^x)dx\uff0c[x\uff1a-1\u21920]
=\u222bxdx-\u222b(e^x)dx\uff0c[x\uff1a-1\u21920]
=(x^2)/2-e^x+C\uff0c[x\uff1a-1\u21920]
=[(0)^2]/2-e^(0)-{[(-1)^2]/2-e^(-1)}
=-1-1/2+1/e
=(1/e)-3/2
∫ x*e^(-x/a) dx
= ∫ -a * x * d [ e^(-x/a) ]
= -a * x * e^(-x/a) + ∫ a * e^(-x/a) dx
=-a * x * e^(-x/a) - a^2 * e^(-x/a)
代入后容易得到积分结果=a^2
(假定a>0,a<0发散)
用r函数=y^2
的法国大范甘迪
绛旓細姝ゅy鐢╝琛ㄧず,鐢ㄥ垎閮ㄧН鍒嗗叕寮忥細鈭 x*e^(-x/a) dx 锛 鈭 锛峚 * x * d [ e^(-x/a) ]锛 锛峚 * x * e^(-x/a) + 鈭 a * e^(-x/a) dx锛濓紞a * x * e^(-x/a) 锛 a^2 * e^(-x/a)浠e叆鍚庡鏄撳緱鍒扮Н鍒嗙粨鏋滐紳a^2(鍋囧畾a>0,a...
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绛旓細鈭玿e^(-k²x²) dx 0鍒版鏃犵┓ = (1/2)鈭玡^(-k²x²) d(x²)= (1/2)(1/-k²)鈭玡^(-k²x²) d(-k²x²)= -1/(2k²)*e^(-k²x²)= -1/(2k²)*(0-e^0)= 1/(2k²)...
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