已知x一2的平方根加y减8的绝多值加6减2的平方根=0,求x十y十z的平方，答是多少
\u5df2\u77e5x\u51cf\u4e00\u7684\u7edd\u5bf9\u503c\u52a0y\u51cf2\u7684\u5e73\u65b9\u52a0z+3\u7684\u5e73\u65b9\u6839\u7b49\u4e8e0\u6c42xy+z²\u7684\u5e73\u65b9\u6839|x-1| + (y-2)^2 + \u221a(z+3) = 0
\u7531\u4e8e\u7edd\u5bf9\u503c\u3001\u5e73\u65b9\u3001\u6839\u53f7\u4e0d\u80fd\u662f\u8d1f\u6570\uff0c\u800c\u4e09\u8005\u7684\u548c\u662f0\uff0c\u6240\u4ee5
|x-1| = (y-2)^2 = \u221a(z+3) = 0
\u6240\u4ee5x = 1\uff0cy=2\uff0cz = -3
\u6240\u4ee5\u221a(xy+z²) = \u221a11
\u7531x-y\u7684\u7b97\u672f\u5e73\u65b9\u6839\u7b49\u4e8e2,
\u5f97x-y=4
\u7531x+y\u7684\u7acb\u65b9\u6839\u7b49\u4e8e3,
\u5f97x+y=27,
\u89e3\u5f97,x=31/2,y=23/2,
x\u7684\u5e73\u65b9\u51cfy\u7684\u5e73\u65b9\u51cf8
=(31/2)^2-(23/2)^2-8\u7684\u7b97\u672f\u5e73\u65b9\u6839
=100\u7684\u7b97\u672f\u5e73\u65b9\u6839
=10
所以x=2，y=8，z=6
所以答案是256.
绛旓細鎵浠=2锛y=8锛寊=6 鎵浠ョ瓟妗堟槸256.
绛旓細宸茬煡x-2鐨勫钩鏂规牴鏄璐2锛y-2x-8鐨勭珛鏂规牴鏄-3 鎵浠ワ紝x - 2 = 4,y -2x -8 = -27 x = 6, y = -7 x�0�5 + 1/y�0�5 = 6�0�5 + 1/(-7)�0�5 = 36 + 1/49 = (36鍙49鍒嗕箣1)
绛旓細鏍瑰彿锛坸-2)+/y+8/=0锛屾墍浠=2锛寉=-8銆傚垯鏍瑰彿(x浜屾鏂-2xy+y浜屾鏂)=|x-y|=10锛屾墍浠骞虫柟鏍涓烘璐熸牴鍙10
绛旓細鐢眡-y鐨勭畻鏈钩鏂规牴绛変簬2,寰梮-y=4 鐢眡+y鐨勭珛鏂规牴绛変簬3,寰梮+y=27,瑙ｅ緱,x=31/2,y=23/2,x鐨勫钩鏂瑰噺y鐨勫钩鏂瑰噺8 =(31/2)^2-(23/2)^2-8鐨勭畻鏈钩鏂规牴 =100鐨勭畻鏈钩鏂规牴 =10
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绛旓細鐢X-2鐨勫钩鏂规牴鏄璐2锛屽彲寰x=6 鍐嶇敱y-2x-8鐨绔嬫柟鏍规槸-3锛屽彲寰梱=-7 鏁厁鐨勫钩鏂+y鐨勫钩鏂=85
绛旓細X鍑2鐨勫钩鏂规牴鏄璐2锛Y鍑2X鍑8鐨绔嬫柟鏍规槸璐3 鈭x-2=(卤2)²=4 y-2x-8=(-3)³鍗硏=6 y=-11 X鍑廦鐨勭畻鏁板钩鏂规牴 =鈭氾箼6+11)=鈭17
绛旓細鍚屽蹇潯瑙夊惂
绛旓細鈭(x-2)+(y+1)^2=0 涓ら」鍧囬潪璐,鍜屼负0,鍒欏潎涓0 鈭磝-2=0涓攜+1=0 鈭磝=2,y=-1 鈭磝-y=3
