求解:将若干本练习本分给若干名学生,若每人4本,则余20本。若每人8本,则有一人分到不到8本。的列式 将若干本练习本分给若干名同学,如果每人分4本,那么还余20本...
\u5c06\u82e5\u5e72\u672c\u7ec3\u4e60\u672c\u5206\u7ed9\u82e5\u5e72\u540d\u540c\u5b66\uff0c\u5982\u679c\u6bcf\u4eba\u52064\u672c\uff0c\u90a3\u4e48\u8fd8\u4f5920\u672c \uff0c\u5c06\u82e5\u5e72\u672c\u7ec3\u4e60\u672c\u5206\u7ed9\u82e5\u5e72\u540d\u540c\u5b66,\u5982\u679c\u6bcf\u4eba\u52064\u672c,\u90a3\u4e48\u8fd8\u4f5920\u672c ,\u5982\u679c\u6bcf\u4eba\u52068\u672c,\u90a3\u4e48\u6700\u540e\u4e00\u540d\u540c\u5b66\u5206\u5230\u7684\u4e0d\u8db38\u672c,\u6c42\u5b66\u751f\u4eba\u6570\u548c\u7ec3\u4e60\u672c\u6570
\u89e3\uff1a\u8bbe\u5b66\u751f\u6709X\u4eba
4X+20=8(X-1)+4
4X+20=8X-4
4X=24
X=6
\u5b66\u751f=6\u4eba
\u7ec3\u4e60\u672c=6\u00d74+20=44\u4eba
\u89e3:\u8bbe\u5171\u6709X\u4e2a\u5b66\u751f,\u5219\u5171\u6709\u7ec3\u4e60\u672c(4X+20)\u672c.
\u6839\u636e\u9898\u610f\u5f97: 0<4X+20-8(X-1)<8.
\u89e3\u5f97: 5<X<7.
\u6240\u4ee5\u6574\u6570X\u4e3a6,\u5373\u5171\u67096\u540d\u5b66\u751f,\u7ec3\u4e60\u672c\u67094X6+20=44(\u672c).
绛旓細鍋囪鏈4涓汉 4x4=16+20=36 36梅8=4鏈...4鏈
绛旓細4x+20=y (1)8x+b=y (b<8)(2)(2)-(1)寰4x+b-20=0 x=(20-b)/4 鍥犱负b<8,涓攛涓烘暣鏁 b=4
绛旓細璁炬湁涓鍏辨湁X涓悓瀛,鍒欐湁鏂圭▼锛5X+12=8X-6 瑙e緱锛歑=6 涓鍏辨湁5*6+12=42涓湰瀛
绛旓細锛7+5锛壝2锛6鍚嶅悓瀛︼紝6脳5+7锛37鏈粌涔犳湰銆傚皬瀛︽暟瀛︾煡璇嗚鐐 鏁 鏁存暟銆佽嚜鐒舵暟銆佹鏁般佽礋鏁般佸垎鏁般佸皬鏁 鐧惧垎鏁 銆傝鏁板崟浣嶅拰鏁颁綅 璁℃暟鍗曚綅銆佹暟浣嶃佸崄杩涘埗璁℃暟娉曘傛暟鐨勬敼鍐欙紙鐪佺暐锛1.鎶婂浣嶆暟鏀瑰啓鎴愨滀竾鈥濄佲滀嚎鈥濈洿鎺ユ敼鍐欙細鍏堟妸鍘熸暟灏忔暟鐐瑰悜宸︾Щ鍔4浣嶆垨8浣嶏紙灏忔暟閮ㄥ垎鐨勬湯灏炬槸0瑕佸垝鎺夛級锛...
绛旓細璁惧悓瀛, 缁冧範鏈y 3x +80=y 5x -5<y 5x >y x,y 涓烘暣鏁 x 涓41 鏈鍚庡悓瀛﹀墿浣3 y 涓203 x 涓42 鏈鍚庡悓瀛﹀墿浣1 y 涓206
绛旓細nX5-1=nX3+80; 鈫抧=鏃犳暣鏁拌В nX5-2=nX3+80; 鈫抧=41 nX5-3=nX3+80; 鈫抧=鏃犳暣鏁拌В nX5-4=nX3+80; 鈫抧=42
绛旓細濡傛灉闂渶澶氬彲鍒嗙粰澶氬皯浜虹殑璇濓紝灏辨槸姹備袱鑰呯殑鏈澶у叕鍥犳暟锛48涓64鐨勬渶澶у叕鍥犳暟涓16锛屾墍浠ヤ负16浜
绛旓細璁捐繖涓彮鏈塜涓鐢燂紝Y鏈粌涔犳湰 鐢遍鍙煡锛5X+25=Y;6X+20=Y 涓ゅ紡浠e叆寰 5X+25=6X+20 X=5 鎵浠ユ湁5涓鐢 Y=5*5+25=50 鎵浠ユ湁50鏈粌涔犳湰
绛旓細x鍚嶅悓瀛︼紝5x+17=7x-5 寰梮=11 鎵浠ユ湁11鍚嶅悓瀛︼紝72鏈粌涔犳湰銆
绛旓細涓鍏辨湁5涓鐢熸垨6涓鐢熴傝鏈塜涓鐢燂紝Y鏈粌涔犳湰銆3X+8=Y 5X>Y 5(X-1)<Y 瑙e緱 4<X<6.5 褰揦锛5鏃讹紝Y锛23锛屼竴涓鐢熷垎5鏈椂锛屽墠4浜哄垎20鏈紝鍚庝竴浜哄垎3鏈傚綋X锛6鏃讹紝Y锛26锛屼竴涓鐢熷垎5鏈椂锛屽墠5浜哄垎25鏈紝鍚庝竴浜哄垎1鏈