两道因式分解的数学难题不会，求数学学霸指点指点！（步骤完整即采纳） 用分解因式的方法解下列问题，请求学霸指点，谢谢！
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则原式=2a² + 5ab + 2b²
用十字相乘法得：上式=(2a+b)(a+2b)
代回得：(2a+b)(a+2b)
=[2(x²+6x+1)+(x²+1)][(x²+6x+1)+2(x²+1)]
=(2x²+12x+2+x²+1)(x²+6x+1+2x²+2)
=(3x²+12x+3)(3x²+6x+3)
=3(x²+4x+1)•3(x²+2x+1)
=9(x²+4x+1)(x+1)²
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绛旓細factor((-x+y)^3-y*(x+y)^2+(y+x)*x^2)ans = x*y*(-5*y+3*x)
