输入三个正整数,判断其奇偶性并输出结果。 输入三个整数,判断它们的奇偶(函数判断并输出一个数的奇偶) ...
C\u8bed\u8a00\u9898 \u8f93\u5165\u4e00\u4e2a\u6b63\u6574\u6570\uff0c\u5224\u65ad\u5176\u5947\u5076\u6027\u5e76\u8f93\u51fa \u5e0c\u671b\u5199\u4e0b\u7a0b\u5e8f \u975e\u5e38\u611f\u8c22#include int main(){ int i; scanf("%d",&i);//\u8f93\u5165 if(i%2==0)printf("\u5076\u6570\n"); else printf("\u5947\u6570\n"); return 0; }
#include int isOdd(int n){ if(n%2==0)return 0; else return 1;}int main(){ int a, b, c; scanf("%d%d%d", &a, &b, &c); if(isOdd(a))printf("%d is odd\n", a); else printf("%d is even\n", a); if(isOdd(b))printf("%d is odd\n", b); else printf("%d is even\n", b); if(isOdd(c))printf("%d is odd\n", c); else printf("%d is even\n", c); return 0;}
不知道楼主想要的是什么语言的,楼上是用c++写的,那我给个c的吧#include<stdio.h>
int main()
{
int a,i;
for(i=0;i<3;i++){
printf("请输入一个数字,并以回车结束");
scanf("%d",&a);
if(a%2)
printf("%d 是奇数");
else
printf("%d 是偶数");
}
return;
}
另外楼上的程序稍稍有点小错误,if和else的内容需要互换一下
#include<iostream.h>
void main()
{
int a[3],i=3;
cout<<"输入3个正整数,每个正整数以回车键结束"<<endl;
while(i--)
{
cin>>a[i-1];
if(a[i-1]%2)
cout<<endl<<a[i-1]<<"为偶数"<<endl;
else
cout<<endl<<a[i-1]<<"为奇数"<<endl;
}
}
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绛旓細鍒╃敤濂囧伓鏁扮殑鐗规э紝瀵2妯¢櫎锛屽彲浠ユ暣闄ょ殑涓哄伓鏁帮紝鍚﹀垯涓哄鏁般備唬鐮侊細include <stdio.h>int main(){ int a; scanf("%d",&a); if(a%2==0) printf("鍋舵暟\n"); else printf("濂囨暟\n"); return 0;}
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