求矩阵的秩的时候可以混合使用初等行变换和初等列变换吗? 矩阵的初等行变换和列变换混用求矩阵的秩

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可以。

在线性代数中,一个矩阵A的列秩是A的线性独立的纵列的极大数目。类似地,行秩是A的线性无关的横行的极大数目。即如果把矩阵看成一个个行向量或者列向量,秩就是这些行向量或者列向量的秩,也就是极大无关组中所含向量的个数。

A=(aij)m×n的不为零的子式的最大阶数称为矩阵A的秩,记作rA,或rankA或R(A)。特别规定零矩阵的秩为零。显然rA≤min(m,n) 易得:若A中至少有一个r阶子式不等于零,且在r<min(m,n)时,A中所有的r+1阶子式全为零,则A的秩为r。

由定义直接可得n阶可逆矩阵的秩为n,通常又将可逆矩阵称为满秩矩阵, det(A)≠0;不满秩矩阵就是奇异矩阵,det(A)=0。由行列式的性质知,矩阵A的转置AT的秩与A的秩是一样的,即rank(A)=rank(AT)。

扩展资料:

矩阵的秩的性质:

1、转置后秩不变;

2、r(A)<=min(m,n),A是m*n型矩阵;

3、r(kA)=r(A),k不等于0;

4、r(A)=0 <=> A=0;

5、r(A+B)<=r(A)+r(B);

6、r(AB)<=min(r(A),r(B));

7、r(A)+r(B)-n<=r(AB)。



若题目让求一个矩阵阶梯形矩阵和约化的阶梯形矩阵

则只能用初等行变换.


只求矩阵的秩的话, 可以行列变换混用

不过行变换足够用了

若求极大无关组或解线性方程组, 则只能用初等行变换


有列阶梯矩阵这一说, 但大部分教材不提它


行阶梯形:



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