tan0,tan（π/2）,tanπ,tan（3π/2）,tan2π分别等于多少来着？ tan(-α+3/2π)怎么化简
\u4e3a\u4ec0\u4e48tan90\u5ea6=tan(\u03c0/2)?90\u5ea6\u548c\u03c0/2\u8868\u793a\u4e00\u6837\u7684\u89d2\u5ea6\u3002\u4ed6\u4eec\u7684\u6b63\u5207\u503c\u5f53\u7136\u76f8\u540c\u4e86\u3002
\u89d2\u7684\u5ea6\u91cf\u6709\u5f27\u5ea6\u6cd5\u548c\u89d2\u5ea6\u6cd5\u3002
\u89d2\u5ea6\u6cd5\u5c31\u662f\u5c06\u5706\u5468\u5206\u6210360\u7b49\u5206\uff0c\u6bcf\u4e00\u7b49\u5206\u5c31\u662f1\u5ea6\u3002
\u5f27\u5ea6\u6cd5\u662f\u5c06\u89d2\u6240\u5bf9\u5e94\u5f27\u957f\u4e8e\u534a\u5f84\u4e4b\u6bd4\u4f5c\u4e3a\u8f83\u5927\u5c0f\u7684\u5355\u4f4d\u3002\u56e0\u5143\u7684\u5468\u957f\u4e3a2\u03c0r\uff0c\u6240\u4ee5\u6574\u4e2a\u5706\u5468\u7684\u5927\u5c0f\u5c31\u662f2\u03c0\u5f27\u5ea6\u3002
tan(-\u03b1+3/2\u03c0)=-tan[2\u03c0-(-\u03b1+3/2\u03c0)]=-tan(a-\u03c0/2)=tan(\u03c0/2-a)=cota
tan0 = 0tan（π/2） = 正无穷大
tanπ = 0
tan（3π/2）= 负无穷大
tan2π = tan0 = 0
绛旓細tan0 = 0 tan锛埾/2锛 = 姝ｆ棤绌峰ぇ tan蟺 = 0 tan锛3蟺/2锛= 璐熸棤绌峰ぇ tan2蟺 = tan0 = 0
绛旓細tan0鏄瓨鍦ㄣtan(0掳) = 0 銆傝绠楁柟寮忓涓嬶細tan0=sin0/cos0=0/1=0銆俆an鏄鍒囩殑鎰忔濓紝瑙捨稿湪浠绘剰鐩磋涓夎褰腑锛屼笌胃鐩稿搴旂殑瀵硅竟涓庨偦杈圭殑姣斿煎彨鍋氳胃鐨勬鍒囧笺傝嫢灏單告斁鍦ㄧ洿瑙掑潗鏍囩郴涓嵆tan胃=y/x锛宼anA=瀵硅竟/閭昏竟锛屽湪鐩磋鍧愭爣绯讳腑鐩稿綋浜庣洿绾跨殑鏂滅巼k銆倀an涓夎鍑芥暟鍏紡锛歵an^2(伪锛2)...
绛旓細tan0搴=0 锛宼an90搴︿笉瀛樺湪銆倀an锛2k蟺+伪锛=tan 伪 tan(蟺/2-伪锛=cot 伪 tan锛埾/2+伪锛=-cot 伪 tan锛埾+伪锛=tan 伪 tan锛埾-伪锛=-tan 伪 鑻ュ皢胃鏀惧湪鐩磋鍧愭爣绯讳腑鍗硉an胃=y/x銆倀anA=瀵硅竟/閭昏竟銆傚湪鐩磋鍧愭爣绯讳腑鐩稿綋浜庣洿绾跨殑鏂滅巼k銆傚皢瑙掑害涔樹互 蟺/180 鍗冲彲杞崲涓哄姬搴︼紝灏嗗姬...
绛旓細0搴﹁锛tan0掳=0锛arctan0=0掳 30搴﹁锛歵an30掳=鈭3/3锛宎rctan(鈭3/3)=30掳 45搴﹁锛歵an45掳=1锛宎rctan1=45掳 60搴﹁锛歵an60掳=鈭3锛宎rctan鈭3=60掳
绛旓細蟺鍒嗕箣2锛熻繕鏄2鍒嗕箣蟺锛熷鏋滄槸蟺鍒嗕箣2鐨勮瘽杩欎釜鍩烘湰涓嶄細娑夊強 灏辩畻绛旀鏄繖涓氨鐩存帴鍐櫹鍒嗕箣2灏辫 tan2鍒嗕箣蟺鏃犳剰涔 涔熷氨鏄笉瀛樺湪
绛旓細蟺绾︾瓑浜3.141592653锛屾槸鍦嗗懆鐜囷紝浠ｈ〃鍦嗗懆闀垮拰鐩村緞鐨勬瘮鍊笺傚畠鏄竴涓棤鐞嗘暟锛屽嵆鏃犻檺涓嶅惊鐜皬鏁般傁涔熺瓑浜庡渾褰箣闈㈢Н涓庡崐寰勫钩鏂逛箣姣旓紝鏄簿纭绠楀渾鍛ㄩ暱銆佸渾闈㈢Н銆佺悆浣撶Н绛夊嚑浣曞舰鐘剁殑鍏抽敭鍊笺倀an鍑芥暟鏄竴涓鍑芥暟锛屽浜庝换浣曞疄鏁皒锛岄兘鏈tan(-x)=-tanx銆傦紝濡傛灉tanx>0锛閭ｄ箞tan(-x)0銆傚洜涓合鏄2蟺鐨勪竴...
绛旓細tan胃=y/x銆tan(0)=0銆傚湪Rt鈻矨BC锛堢洿瑙掍笁瑙掑舰锛変腑锛屸垹C=90掳锛孉B鏄垹C鐨勫杈筩锛孊C鏄垹A鐨勫杈筧锛孉C鏄垹B鐨勫杈筨锛屾鍒囧嚱鏁板氨鏄痶anB=b/a锛屽嵆tanB=AC/BC銆傚湪Rt鈻矨BC涓紝濡傛灉閿愯A纭畾锛岄偅涔堣A鐨勫杈逛笌閭昏竟鐨勬瘮鍊奸殢涔嬬‘瀹氾紝杩欎釜姣斿彨鍋氳A鐨勬鍒囷紝璁颁綔tanA銆倀an30掳=鈭3/3锛堝嵆锛氫笁鍒...
绛旓細鍦ㄧ墿鐞嗗涓紝涓夎鍑芥暟涔熸槸甯哥敤鐨勫伐鍏枫傚畠鏈夊叚绉嶅熀鏈嚱鏁般傚嚱鏁板悕姝ｅ鸡浣欏鸡姝ｅ垏浣欏垏姝ｅ壊浣欏壊銆傜鍙 sin cos tan cot sec csc銆傛寮﹀嚱鏁皊in锛圓锛=a/c銆備綑寮﹀嚱鏁癱os锛圓锛=b/c銆傛鍒囧嚱鏁tan锛A锛=a/b銆備綑鍒囧嚱鏁癱ot锛圓锛=b/a銆傚叾涓璦涓哄杈癸紝b涓洪偦杈癸紝c涓烘枩杈广
绛旓細cos(5蟺/3) = 1/2 cos(7蟺/4) = 鈭2/2 cos(11蟺/6) = 鈭3/2 姝ｅ垏鍑芥暟锛坱an锛夌殑鐗规畩鍊硷細tan(0) = 0 tan(蟺/6) = 1/鈭3 tan(蟺/4) = 1 tan(蟺/3) = 鈭3 tan(蟺/2) = 鏃犵┓澶 tan(2蟺/3) = -鈭3 tan(3蟺/4) = -1 tan(5蟺/6) = -1/鈭3 tan(蟺) ...
绛旓細sin2蟺=0锛tan0=0锛tan蟺涓嶅瓨鍦 tan伪 路cot伪锛1 sin伪 路csc伪锛1 cos伪 路sec伪锛1 鍟嗙殑鍏崇郴锛歴in伪/cos伪锛漷an伪锛漵ec伪/csc伪 cos伪/sin伪锛漜ot伪锛漜sc伪/sec伪 骞虫柟鍏崇郴锛歴in^2(伪)锛媍os^2(伪)锛1 1锛媡an^2(伪)锛漵ec^2(伪)1锛媍ot^2(伪)锛漜sc^2(伪)...
