计算浓度为0.1molL-1的盐酸、硫酸、醋酸（醋酸的电离度约1%）三种溶液中氢离子浓度？pH值为多少 今有浓度均为0.1mol/L的醋酸、盐酸和硫酸三种稀溶液，按...
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盐酸PH=1,硫酸，考虑到二级电离，ph=0.94，氢离子浓度0.115mol/L,HAc， 氢离子浓度1.32*10^-3,PH=2.88绛旓細鐗╄川鐨勯噺涓0.1mol锛屾憾娑茶川閲忎负1000g锛屼絾鏄～閰告憾娑茬殑瀵嗗害澶т簬1g/mL锛屾憾娑茬殑浣撶Н灏忎簬1L锛屾墍浠ユ憾娑茬殑鐗╄川鐨勯噺娴撳害澶т簬0.1mol/L锛屾晠B閿欒锛汣銆8g涓夋哀鍖栫～鐗╄川鐨勯噺涓猴細8g80g/mol=0.1mol锛屾憾浜庢按骞堕厤鎴1L婧舵恫锛
绛旓細H2A = H+ + HA- [H+] = [ C锛圚2A) Ka1]^1/2 = (1*1.3脳10-7)^1/2 = 3.6*10^-4 2銆侊蓟A2-锛解増 Ka2 = 7.1脳10-15
绛旓細)锛巆(H+)=KwKa=10?141.7脳10?5=5.9脳10-10锛屾晠绛旀涓猴細5.9脳10-10锛涳紙3锛塸H=3鐨勯唻閰稿拰pH=11鐨勬阿姘у寲閽犳憾娑蹭腑锛岄唻閰娴撳害澶т簬姘㈡哀鍖栭挔锛屼簩鑰呯瓑浣撶Н娣峰悎锛岄唻閰歌繃閲忥紝瀵艰嚧娣峰悎婧舵恫鍛堥吀鎬э紝婧舵恫涓瓨鍦ㄧ墿鏂欏畧鎭掑拰鐢佃嵎瀹堟亽锛屾牴鎹數鑽峰畧鎭掑緱c锛圢a+锛+c锛...
绛旓細L-1锛岄唻閰告槸寮遍吀閮ㄥ垎鐢电锛屽叾姘㈢瀛娴撳害灏忎簬0.1mol?L-1锛屾墍浠ユ阿绂诲瓙娴撳害鐢卞ぇ鍒板皬鐨勯『搴忔槸bac锛屾晠绛旀涓猴細bac锛涳紙2锛塇Cl+NaOH=NaCl+H2O锛孒2SO4+2NaOH=Na2SO4+2H2O锛孋H3COOH+NaOH=CH3COONa+H2O鏍规嵁鐩愰吀銆佺～閰搞侀唻閰镐笌NaOH婧舵恫鍙嶅簲鐨勬柟绋嬪紡鍙煡锛岀～閰镐笌姘㈡哀鍖栭挔鍙嶅簲鏃舵秷鑰楃殑纭吀浣撶Н鏈灏忥紝鐩愰吀鍜岄唻...
绛旓細锛1锛夊娓╀笅鍦╬H=12鐨凬aCN婧舵恫涓紝姘㈡哀鏍圭瀛娴撳害涓锛10-2mol/L锛屾憾娑蹭腑姘㈡哀鏍圭瀛愪负姘寸數绂荤殑锛岀敱姘寸數绂荤殑c锛圤H-锛=10-2mol/L锛屾晠绛旀涓猴細10-2锛 锛2锛夆憼鈶♀懀涓洪摰鐩愶紝鈶负寮辩⒈姘ㄦ按锛屾憾娑蹭腑閾电瀛愭祿搴︹憿姘ㄦ按鐨勬渶灏忥紱鑰屸憽涓阿绂诲瓙鎶戝埗浜嗛摰绂诲瓙姘磋В锛屾憾娑蹭腑鐨勯摰绂诲瓙娴撳害鏈澶э紝鈶ｄ腑閾电瀛愪笌...
绛旓細鍥犱负涓ゆ憾娑茬瓑娣峰悎锛屽垰濂藉畬鍏ㄥ弽搴擭H3路H2O+HCl==NH4Cl+H2O 鍏跺疄鐢熸垚鐨勬渶缁堜骇鐗╂槸NH4Cl鐨勬按婧舵恫 浼氬彂鐢熸按瑙 鏈夛細NH4+ +H2O==NH3路H2O+H+鏍规嵁璐ㄥ瓙瀹堟亽 H2O銆===銆婬+ +OH-鐢电鍑烘潵鐨凥+鍜孫H-閮界浉绛 鑰屾憾娑蹭腑鐨凥+閮芥槸鏈夋按鐢电鐨 鑰屾按鐢电鍑烘潵鐨凮H-鏈変袱涓幓鍚戯細涓涓瓨鍦ㄦ憾娑蹭腑锛屼竴涓窡NH4+缁撳悎...
绛旓細瀹為獙瀹ゆ病鏈480mL瀹归噺鐡讹紝闇瑕侀夌敤500mL瀹归噺鐡讹紝閰嶅埗鐨勬憾娑蹭负锛500ml 0.1mol/L鐨Na2CO3婧舵恫锛岄渶瑕佹憾璐ㄧ⒊閰搁挔鐨勭墿璐ㄧ殑閲忎负锛0.1mol/L脳0.5L=0.05mol锛岄渶瑕佹憾璐ㄧ⒊閰搁挔鐨勮川閲忎负锛106g/mol脳0.05mol=5.3g锛涜嫢绉伴噺甯︾粨鏅舵按鐨勭⒊閰搁挔锛屽垯Na2CO3?10H2O鏅朵綋璐ㄩ噺涓猴細286g/mol脳0.05mol=14.3g锛嶢銆...
绛旓細L-1鐨NaHSO4婧舵恫涓垯n锛圢aHSO4锛=0.1L脳0.1mol?L-1=0.01mol锛屾牴鎹2NaHSO4+Ba锛圤H锛2=BaSO4鈫+Na2SO4+2H2O鍙煡锛屽弬鍔犲弽搴旂殑n[Ba锛圤H锛2]=0.01mol脳12=0.005mol锛岀敓鎴愮殑n锛圔aSO4锛=0.01mol脳12=0.005mol锛屾晠闇瑕丅a锛圤H锛2婧舵恫鐨勪綋绉负0.005mol0.2mol/L=0.025L=25mL锛岀敓鎴...
绛旓細0.1mol/L鐨HA婧舵恫 鑻A瀹屽叏鐢电 HA == H+ + Ac- H+娴撳害涓0.1mol/L pH=-lg[H+]=1 鎵浠ュ綋pH=1锛岃鏄嶩A瀹屽叏鐢电锛屽湪姘存憾娑蹭腑瀹屽叏鐢电鐨勭數瑙ｈ川鏄己鐢佃В璐ㄣ
绛旓細c(Na + ) =" 0.2" mol路L -1 锛屽皢CO 2 閫氬叆0.1 mol路L -1 Na 2 CO 3 婧舵恫涓嚦婧舵恫涓,姝ゆ椂CO 2 杩囬噺锛屽弽搴旂敓鎴愪簡NaHCO 3 锛屾鏃讹紝婧舵恫鐨勪綋绉版病鏈夊彉锛屾憾娑蹭腑鐨勯挔绂诲瓙鐨娴撳害浠嶇劧涓猴細c(Na + ) ="0.2" mol路L -1 锛屾牴鎹數鑽峰畧鎭掓湁锛歝(Na + ) + c(H + ) =" c" ...
