要配制0.10mol/L的HCL溶液1000ml，需要密度为1.19g/立方厘米，质量分数为0.3
\u8981\u914d\u52360.10mol/L\u7684HCL\u6eb6\u6db21000ml,\u9700\u8981\u5bc6\u5ea6\u4e3a1.19g/\u5e73\u65b9\u5398\u7c73,\u8d28\u91cf\u5206\u662f\u4e2a0.37\u7684\u6d53\u76d0\u9178\u591a\u5c11\u6beb\u5347HCL \u97000.10*1=0.1mol
\u537336.5g/mol*0.1mol=3.65g
so
v=3.65/1.19
=3.067ml
v=8.2898*10^(-3)L=8.2898ml
绛旓細棣栧厛璁＄畻37%鐩愰吀鐨勭墿璐ㄧ殑閲忔祿搴=1000*1.18*37%/36.5=12.0mol/L 鍒╃敤绋閲婂叕寮忥細c1v1=c2v2锛岃绠楁墍闇娴撶洂閰哥殑浣撶Н锛寁1=c2v2/c1=0.10*1000/12=8.33姣崌銆
绛旓細涔抽吀閽犲垎瀛愰噺涓112锛屽嵆鎽╁皵璐ㄩ噺涓112g/mol銆傞偅涔0.10mol/L涔抽吀閽犳祿搴︿篃灏辨槸112*0.10=11.2g/L锛屽嵆0.0112g/ml銆250ml涔抽吀閽犳憾娑叉墍鍚憾璐ㄤ负0.0112*250锛坓锛夋墍浠ラ渶鐢112g/L涔抽吀閽犳憾娑茬殑浣撶Н涓0.0112*250/112=0.025锛圠锛0.025L涔熷氨鏄25ml銆
绛旓細閰嶅埗500ml 0.10mol/l :A涓烘纭搷浣滐紱B瀹归噺鐡朵腑鐨勬按涓嶅奖鍝嶆憾娑茬殑浣撶Н锛汣鍙犳垚婧惰川鐨勬崯澶憋紱D鍙娇瀹為檯瀹圭Н鍋忎綆,娴撳害鍋忛珮锛汦鍙犳垚婧惰川鐨勬崯澶.鍥犳姝ｇ‘绛旀涓猴細C鍜孍.蹇呴』鐢ㄥ埌鐨勪华鍣ㄥ湪璇炬湰灏辨湁.
绛旓細閰嶅埗涓瀹氱墿璐ㄧ殑閲忔祿搴︽憾娑茬殑姝ラ锛氱О閲忋佹憾瑙ｃ佸喎鍗淬佺Щ娑层佹礂娑ゃ佸畾瀹广佹憞鍖绛夛紝鈶犵О閲忔阿姘у寲閽犳椂锛屽洜涓烘阿姘у寲閽犳憾娑叉疆瑙ｅ彉璐紝搴旂敤灏忕儳鏉О閲忥紱鈶ｇ幓鐠冩寮曟祦鏃讹紝涓嬬搴旈潬鍦ㄥ埢搴︾嚎浠ヤ笅锛涒懁瀹氬鏃讹紝搴斿钩瑙嗗埢搴︾嚎锛涙晠閫夛細C锛
绛旓細绛旀锛欱锛庡亸浣 瑙ｏ細鐢卞ぉ骞崇О閲忚鍒欎负锛氳嵂鍝佽川閲=鐮濈爜璐ㄩ噺+娓哥爜璐ㄩ噺銆傝嫢鐮濈爜涓庤嵂鍝侀鍊掞紝鍒欒嵂鍝佽川閲+娓哥爜璐ㄩ噺=鐮濈爜璐ㄩ噺锛屽疄闄呯О寰楁牱鍝佺殑璐ㄩ噺涓猴細鐮濈爜璐ㄩ噺-娓哥爜璐ㄩ噺=5.0g-0.3g=4.7g锛岀О閲忕殑纰抽吀閽犺川閲忓亸灏忥紝鏈缁閰嶅埗鐨勭⒊閰搁挔婧舵恫娴撳害鍋忎綆銆傚欢浼革細澶╁钩浣跨敤瑙勫垯锛1.搴旀牴鎹О閲忚姹傜殑绮惧害鍜岃绉扮墿浣撶殑璐ㄩ噺...
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