用python如何从四个给定的单词里随机显示一个 python的random能实现在几个数中随机选取一个吗?帮...

python\u4e2d\u600e\u6837\u4ece\u4e00\u4e9b\u5b57\u7b26\u4e32\u4e2d\u968f\u673a\u9009\u62e9\u4e00\u4e2a\u8f93\u51fa

\u4ee5\u4e0b\u662f\u793a\u4f8b\u4ee3\u7801\uff1a
import randomstr1='this_a_string_with_several_characters'n=random.randint(0,len(str1))print(str1[n])#\u8fd4\u56de\u4e00\u4e2a\u5b57\u7b26\u4e32\u968f\u673a\u4f4d\u7f6e\u7684\u5b57\u7b26strs=['str1','str2','str3','str4','str5','str6']n=random.randint(0,len(strs))print(strs[n])#\u8fd4\u56de\u4e00\u4e2a\u5b57\u7b26\u4e32\u6570\u7ec4\u968f\u673a\u4f4d\u7f6e\u7684\u5b57\u7b26\u4e32\u4e0d\u660e\u767d\u53ef\u8ffd\u95ee

\u53ef\u4ee5\u5440\uff0c\u6bd4\u5982\u4f60\u67095\u4e2a\u6570\u5b57\uff0c\u4e0b\u8868\u662f0\uff0c1\uff0c2\uff0c3\uff0c4\uff0c \u90a3\u4f60\u7528\u968f\u673a\u6570\u4ea7\u751f0\uff0c4\u4e4b\u95f4\u7684\uff0c\u7136\u540e\u7528\u4e0b\u6807\u4e0d\u5c31\u5f97\u5230\u6570\u5b57\u4e86\u5417\uff1frandom\u5305\u91cc\u4e0d\u662f\u6709\u5982\u4e0b\u51fd\u6570\u5417\uff1f

randint( a, b)

Return a random integer N such that a <= N <= b.

#-*- coding: gbk -*-
'''
#=============================================================================
# FileName: rand.py
# Desc: Random display of a word from four words
# Author: cold night
# Email: [email protected]
# HomePage: http://linuxer.blog.51cto.com
# Version: 0.0.1
# LastChange: 2011-11-17 09:45:28
# History:
#=============================================================================
'''

import random

def ShowOne(words):
'''
words:参数是一个包含四个单词的列表
'''
i = random.randint(0,3)
print words[i]

# 防止一闪
raw_input()

# 假设从输入获取依次获取这4个单词
words = []
for i in range(0,4):
words.append(raw_input("Enter a word: "))

ShowOne(words)

直接用rand模块里的choice就行了
比如
from random import choice
lst = ['one', 'two', 'three', 'four']
choice(lst)
就行了

import random

words = ['one','two','three','four']
flag = random.randint(0,3)
print(words[flag])

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