∫(π/2,0)(x^e)*(cosx)dx=?

\u222b(\u4e0b0,\u4e0a\u03c0/4) x/(cosx)^2 dx

\u222bxdx/(cosx)^2= \u222bxdtanx=xtanx-\u222btanxdx=xtanx-\u222bsinxdx/cosx=xtanx+lncosx+C
\u222b[0, \u03c0/4] xdx/(cosx)^2=\u03c0/4-ln\u221a2

=\u222bx(secx)^2dx
=\u222bxdtanx
=xtanx-\u222btanxdx
=xtanx-\u222bsinx/cosxdx
=xtanx+\u222bdcosx/cosx
=xtanx+ln|cosx|+C

∫e^xcosxdx=∫e^xdsinx=e^xsinx-∫sinxe^xdx=e^xsinx+∫e^xdcosx=e^xsinx+e^xcosx-∫e^xcosxdx
2∫e^xcosxdx=e^xsinx+e^xcosx
∫e^xcosxdx=(1/2)e^x(sinx+cosx)
∫[π/2,0] e^xcosxdx= (1/2)-(1/2)e^(π/2)

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