设A、B、C是半径为1的球面上的三点， 设A、B、C是半径为1的球面上的三点,A与B、B与C、C与A...
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通过已知A、B、C是半径为1的球面上的三点可知OA=OB=OC=1。
B、C两点间的球面距离为π/3，可知∠BOC=60°，BC=1
点A与B、C两点间的球面距离均为π/2，可知∠AOB=∠AOC=90°
亦可推出OA⊥面OBC。
O到截面ABC的距离，即过O向△ABC做的垂线距离，
通过△面积可以算出O到截面ABC的距离为：√21/7
距离为1，因为球心到球面的距离就是半径的长度吧，因为ABC都在球的表面，所以最近的距离应该是半径的长吧
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