三角函数和差化积公式？ 数学中三角函数和差化积公式是哪些？
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sinx+siny=2sin[(x+y)/2]cos[(x-y)/2]
sinx-siny=2cos[(x+y)/2]sin[(x-y)/2]
cosx+cosy=2cos[(x+y)/2]cos[(x-y)/2]
cosx-cosy=-2sin[(x+y)/2]sin[(x-y)/2]
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sinxsiny=-1/2[cos(x+y)-cos(x-y)]
cosxcosy=1/2[cos(x+y)+cos(x-y)]
sinxcosy=1/2[sin(x+y)+sin(x-y)]
cosxsiny=1/2[sin(x+y)-sin(x-y)]
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2sinAcosB=sin(A+B)+sin(A-B) 2cosAsinB=sin(A+B)-sin(A-B)
2cosAcosB=cos(A+B)-sin(A-B) -2sinAsinB=cos(A+B)-cos(A-B)
sinA+sinB=2sin((A+B)/2)cos((A-B)/2 cosA+cosB=2cos((A+B)/2)sin((A-B)/2)
tanA+tanB=sin(A+B)/cosAcosB tanA-tanB=sin(A-B)/cosAcosB
cotA+cotBsin(A+B)/sinAsinB -cotA+cotBsin(A+B)/sinAsinB
2sinAcosB=sin(A+B)+sin(A-B) 2cosAsinB=sin(A+B)-sin(A-B)
2cosAcosB=cos(A+B)-sin(A-B) -2sinAsinB=cos(A+B)-cos(A-B)
sinA+sinB=2sin((A+B)/2)cos((A-B)/2 cosA+cosB=2cos((A+B)/2)sin((A-B)/2)
tanA+tanB=sin(A+B)/cosAcosB tanA-tanB=sin(A-B)/cosAcosB
cotA+cotBsin(A+B)/sinAsinB -cotA+cotBsin(A+B)/sinAsinB
绛旓細涓夎鍑芥暟绉寲鍜屽樊鍏紡 sinAsinB=-[cos(A+B)-cos(A-B)]/2 cosAcosB=[cos(A+B)+cos(A-B)]/2 sinAcosB=[sin(A+B)+sin(A-B)]/2 cosAsinB=[sin(A+B)-sin(A-B)]/2 涓夎鍑芥暟绉寲鍜屽樊鎺ㄥ杩囩▼锛歴in(a+b)=sinacosb+cosasinb sin(a-b)=sinacosb-cosasinb 涓ゅ紡鐩稿姞寰楋細sinacosb...
绛旓細cos(伪+尾)=cos伪路cos尾-sin伪路sin尾 cos(伪-尾)=cos伪路cos尾+sin伪路sin尾 sin(伪卤尾)=sin伪路cos尾卤cos伪路sin尾 tan(伪+尾)=(tan伪+tan尾)/(1-tan伪路tan尾)tan(伪-尾)=(tan伪-tan尾)/(1+tan伪路tan尾)鍜屽樊鍖栫Н鍏紡 sin伪+sin尾=2sin[(伪+尾)/2]cos[(伪-尾)...
绛旓細涓夎鍑芥暟鐨勫拰宸寲绉叕寮忔槸鐢ㄦ潵灏嗕袱涓笁瑙掑嚱鏁扮殑鍜屾垨宸浆鍖栦负涔樼Н鐨勫叕寮銆傚叿浣撳叕寮忓涓嬶細1. 涓夎鍑芥暟鐨勫拰宸寲绉叕寮忥細- 姝ｅ鸡鍑芥暟鐨勫拰宸寲绉叕寮忥細sin(A 卤 B) = sinA路cosB 卤 cosA路sinB - 浣欏鸡鍑芥暟鐨勫拰宸寲绉叕寮忥細cos(A 卤 B) = cosA路cosB ∓ sinA路sinB - 姝ｅ垏鍑芥暟鐨勫拰宸寲绉...
绛旓細鍜屽樊鍖栫Н锛sinA-sinB=2sin[(A-B)/2]cos[(A+B)/2]涓よ鍜屽叕寮锛歴in(A+B)=sinAcosB+cosAsinB sin(A-B)=sinAcosB-sinBcosA cos(A+B)=cosAcosB-sinAsinB cos(A-B)=cosAcosB+sinAsinB 鍜屽樊鍖栫Н鍏紡 鍖呮嫭姝ｅ鸡銆佷綑寮︺佹鍒囧拰浣欏垏鐨勫拰宸寲绉叕寮忥紝鏄笁瑙掑嚱鏁颁腑鐨勪竴缁勬亽绛夊紡锛屽拰宸寲绉叕寮...
绛旓細涓夎鍑芥暟鍜岀Н鍖栧樊鍜屽樊鍖栫Н鍏紡濡備笅锛1銆佺Н鍖栧拰宸叕寮忔湁sin伪*cos尾=锛1/2锛塻in锛埼+尾锛+sin锛埼-尾锛锛沜os伪*sin尾=锛1/2锛塻in锛埼+尾锛-sin锛埼-尾锛夛紱cos伪*cos尾=锛1/2锛塩os锛埼+尾锛+cos锛埼-尾锛夛紱sin伪*sin尾=锛1/2锛塩os锛埼+尾锛-cos锛埼-尾锛夈2銆佸樊鍖栫Н鍏紡鏈...
绛旓細涓夎鍑芥暟 鍜屽樊鍖栫Н 2sinAcosB=sin(A+B)+sin(A-B) 2cosAsinB=sin(A+B)-sin(A-B)2cosAcosB=cos(A+B)-sin(A-B) -2sinAsinB=cos(A+B)-cos(A-B)sinA+sinB=2sin((A+B)/2)cos((A-B)/2 cosA+cosB=2cos((A+B)/2)sin((A-B)/2)tanA+tanB=sin(A+B)/cosAcosB tanA-...
绛旓細涓夎鍑芥暟鍜屽樊鍖栫Н鍏紡鏄痵in伪+sin尾=2sin[锛埼+尾锛/2]cos[锛埼-尾锛/2]锛泂in伪-sin尾=2cos[锛埼+尾锛/2]sin[锛埼-尾锛/2]锛沜os伪+cos尾=2cos[锛埼+尾锛/2]cos[锛埼-尾锛/2]锛沜os伪-cos尾=-2sin[锛埼+尾锛/2]sin[锛埼-尾锛/2]銆傚拰宸寲绉叕寮忔槸涓夎鍑芥暟涓殑閲嶈鍏紡...
绛旓細涓夎鍑芥暟 鍜屽樊鍖栫Н 2sinAcosB=sin(A+B)+sin(A-B) 2cosAsinB=sin(A+B)-sin(A-B)2cosAcosB=cos(A+B)-sin(A-B) -2sinAsinB=cos(A+B)-cos(A-B)sinA+sinB=2sin((A+B)/2)cos((A-B)/2 cosA+cosB=2cos((A+B)/2)sin((A-B)/2)tanA+tanB=sin(A+B)/cosAcosB tanA-...
绛旓細涓夎鍑芥暟鐨鍜屽樊鍖栫Н鍏紡 sin伪+sin尾=2sin((伪+尾)/2) 路cos((伪-尾)/2)sin伪-sin尾=2cos((伪+尾)/2) 路sin((伪-尾)/2)cos伪+cos尾=2cos((伪+尾)/2)路cos((伪-尾)/2)cos伪-cos尾=-2sin((伪+尾)/2)路sin((伪-尾)/2)cos伪+cos尾=2cos((伪+尾)/2)路cos((伪...
绛旓細涓夎鍑芥暟鍜屽樊鍖栫Н鍏紡鏈塻in伪+sin尾=2sin[(伪+尾)/2]cos[(伪-尾)/2] sin伪-sin尾=2cos[(伪+尾)/2]sin[(伪-尾)/2] cos伪+cos尾=2cos[(伪+尾)/2]cos[(伪-尾)/2]绛夈備笁瑙掑嚱鏁扮殑鍜屽樊鍖栫Н鏄寚灏嗕袱涓笁瑙掑嚱鏁扮殑鍜屾垨宸浆鍖栦负涓涓笁瑙掑嚱鏁扮殑涔樼Н銆傝繖涓妧宸у湪瑙ｅ喅涓夎鍑芥暟鐨勮繍绠椼...
