数学初中因式分解要过程，悬赏多
\u6570\u5b66\u521d\u4e2d\u77e5\u8bc6,\u56e0\u5f0f\u5206\u89e325m\u5e73\u65b9-n\u5e73\u65b9=(5m-n)(5m+n)
4-4x+x\u5e73\u65b9=(2-x)²
x\u5e73\u65b9-x-12=\uff08x-4)(x+3)
x\u5e73\u65b9+x-12=(x+4)(x-3)
(x-2)\u5e73\u65b9-2(x-2)=(x-2)(x-2-2)=(x-2)(x-4)
x\u5e73\u65b9+3xy+2y\u5e73\u65b9=(x+y)(x+2y)
x\u5e73\u65b9-8x=x(x-8)
4x\u5e73\u65b9-4x+1=(2x-1)²
(2x+3)\u5e73\u65b9-(1-3x)\u5e73\u65b9=(2x-3-1+3x)(2x-3+1-3x)=(5x-4)(-x-2)=-(5x-4)(x+2)
x\u5e73\u65b9-11x+18=((x-2)(x-9)
\u628a\u4e0b\u5217\u65b9\u7a0b\u5316\u4e3a(x+m)\u5e73\u65b9=n\u7684\u5f62\u5f0f,\u518d\u7528\u5f00\u65b9\u6cd5\u6c42\u89e3
x\u5e73\u65b9-4x+3=0
x²-4x+4=1
(x-2)²=1
x-2=\u00b11
x=3\u6216x=1
x\u5e73\u65b9-2x-99=0
x²-2x+1-100=0
(x-1)²=100
x-1=\u00b110
x=11\u6216x=-9
2x\u5e73\u65b9-7x-4=0
x²-7/2x-2=0
x²-7/2x+49/16-49/16-2=0
(x-7/4)²=81/16
x-7/4=\u00b19/4
x=9/4+7/4=4
x=-9/4+7/4=-1/2
\u2234x=4\u6216x=-1/2
3x\u5e73\u65b9-4x-2=0
x²-4/3x-2/3=0
x²-4/3x+4/9-4/9-2/3=0
(x-2/3)²=10/9
x-2/3=\u00b11/3\u221a10
x=2/3\u00b11/3\u221a10
x\u5e73\u65b9-2x-99=0
2x\u5e73\u65b9-7x-4=0
3x\u5e73\u65b9-4x-2=0
1.x²-y²+a²-b²+2ax+2by
=x²+a²+2ax-y²-b²+2by
=(x+a)^2-(y-b)^2
=(x+a+y-b)(x+a-y+b)
2.a²-4ab+4b²-6a+12b+9
=a²-4ab+4b²-6(a-2b)+9
=(a-2b)^2-6(a-2b)+9
=(a-2b-3)^2
1.8a^3-b^3
=(2a-b)(4a^2+2ab+b^2)
2.4\uff08x-y+1)+y(y-2x)
=4x-4y+4+y^2-2xy
=(y^2-4y+4)-2x(2-y)
=(y-2)^2+2x(y-2)
=(y-2)(2x+y-2)
3.a³+1
=(a+1)(a^2-a+1)
4.4x(\u56db\u6b21\u65b9)-13x²+9
=(4x^2-9)(x^2-1)
=(2x-3)(2x+3)(x-1)(x+1)
5.b²+c²+2ab+2ac+2bc
=b²+c²+2bc+2ab+2ac
=(b+c)^2+2a(b+c)
=(b+c)(b+c+2a)
6.3x²+5xy-2y²+x+9y-4
=3x^2+5xy-2y^2+x+9y-4
=(x+2y)(3x-y)+x+9y-4
=(x+2y)(3x-y)+4(x+2y)-(3x-y)-4
=(x+2y-1)(3x-y+4)
=y²(x+1)(x-1)
(2)原式=m²(p-q)-(p-q)
=(p-q)(m²-1)
=(p-q)(m+1)(m-1)
(3)原式=(x²-4xy+4y²)-1
=(x-2y)²-1
=(x-2y+1)(x-2y-1)
(4)原式=(x²+4+4x)(x²+4-4x)
=(x+2)²(x-2)²
1 原式=y^2(x^2-1)
=y^2(x+1)(x-1)
2 原式=(m^2-1)(p-q)
=(m+1)(m-1)(p-q)
3 原式=（x-2y)^2-1
=(x-2y+1)(x-2y-1)
4 原式=（x^2+4)^2-(4x)^2
=(x^2-4x+4)(x^2+4x+4)
=(x+2)^2(x-2)2
绛旓細1銆佸師寮 =锛坸-1)²-(5y)²=(x-1+5y)(x-1-5y)=(x+5y-1)(x-5y-1)2銆佸師寮 =36a²-(25b²+10b+1)=(6a)²-(5b+1)²=(6a+5b+1)(6a-5b-1)3銆佸師寮 =b²-(4a²-4a+1)=b²-(2a-1)²=(b+2a-1)(b-2a+1)4...
绛旓細瑙: (1)鍘熷紡=y²(x²-1)=y²(x+1)(x-1)(2)鍘熷紡=m²(p-q)-(p-q)=(p-q)(m²-1)=(p-q)(m+1)(m-1)(3)鍘熷紡=(x²-4xy+4y²)-1 =(x-2y)²-1 =(x-2y+1)(x-2y-1)(4)鍘熷紡=(x²+4+4x)(x²+4-4x)...
绛旓細1.瀹屽叏骞虫柟寮忥紝褰㈠锛歛^+2ab+b^=(a+b)^ 2.骞虫柟宸叕寮忥紝褰㈠锛歛^-b^=(a+b)(a-b)3.鍗佸瓧鐩镐箻娉曪紝渚嬪锛歺^-3x+2=(x-1)(x-2)4.鎻愬彇鍏鍥犲紡锛渚嬪锛2(a+3)+3(a+3)^=(a+3)銆2+3(a+3)銆(鈥滐季鈥濅负骞虫柟鐨勬剰鎬)锛堝叾瀹鍒濅腑閲屽鏁伴兘鐢ㄨ繖鍑犵鏂规硶,鍏朵粬涓嶆槸寰堝鐢級鍙傝冭祫鏂...
绛旓細=(x^2+x-2004)(x^2-x+1)3).y=1/x x+1/x=1 涔熷氨鏄 x^2-x+1=0 鍙堝洜涓簒^3+1=(x+1)(x^2-x+1)鍥犱负x^2-x+1=0,鎵浠^3+1=0,鎵浠^3=-1 4).鑻ュ彲浠鍥犲紡鍒嗚В锛屽垯涓瀹氬彲浠ュ啓鎴愶紙x+ay+b)(x+cy+d)鐨勫舰寮 鎵浠ュ睍寮鏈墄^2+(a+c)xy+bd+acy^2+(b+d)x+(ad+bc...
绛旓細鐪嬪浘锛屾湜閲囩撼锛孫(鈭鈭)O璋㈣阿
绛旓細1.-a+2a²-a³=-a锛1-2a+a²)=-a锛1-a)²2.9(x+2y)²-25(x-2y)²=锛 3(x+2y) 锛²-锛5(x-2y) 锛²=[3(x+2y)+5(x-2y)][3(x+2y)-5(x-2y)]=(8x-4y)(-2x+16y)=-8(2x-y)(x-8y)3.x²+x+_1/4__=( ...
绛旓細1銆佸畬鍏ㄥ钩鏂瑰紡锛屽舰濡傦細a^+2ab+b^=(a+b)^銆2銆佸钩鏂瑰樊鍏紡锛屽舰濡傦細a^-b^=(a+b)(a-b)銆3銆佸崄瀛楃浉涔樻硶锛屼緥濡傦細x^-3x+2=(x-1)(x-2)銆4銆佹彁鍙栧叕鍥犲紡锛渚嬪锛2(a+3)+3(a+3)^=(a+3)銆2+3(a+3)銆曘5銆佹妸涓涓椤瑰紡鍦ㄤ竴涓寖鍥(濡傚疄鏁拌寖鍥村唴鍒嗚В锛鍗虫墍鏈夐」鍧囦负瀹炴暟)鍖栦负...
绛旓細=锛坸+k)鐨勫钩鏂+(x+k)+1/2鐨勫钩鏂 =锛坸+k+1/2锛夌殑骞虫柟 锛堝埄鐢ㄥ畬鍏ㄥ钩鏂瑰叕寮忥級锛2锛=x[x(x+6)+2(x+8)]=x[x鐨勫钩鏂+6x+2x+16]=x[x鐨勫钩鏂+8x+16]=x(x+4)鐨勫钩鏂 锛3锛=y骞虫柟(y骞虫柟-4)-4y骞虫柟+4y-4y+16 (鍘绘嫭鍙峰緱鍒帮級=y骞虫柟(y骞虫柟-4)-4y骞虫柟+16 =y骞虫柟(y骞虫柟-...
绛旓細(1)鍘熷紡=(x^2+2x+1)+(y^2-6y+9)=(x+1)^2+(y-3)^2=0 鍥犱负涓や釜闈炶礋鏁扮浉鍔犵瓑浜0锛屾墍浠ヨ繖涓や釜鏁村紡鍧囦负0锛堝嵆鍜屼负闆跺潎涓洪浂锛夋墍浠+1=0,x=-1;y-3=0,y=3鎵浠+y=-1+3=2 (2)鍘熷紡=(a^2b^2-a^2)-(b+1)=a^2(b^2-1)-(b+1)=a^2(b+1)(b-1)-(b+1)=(b...
绛旓細绗竴棰橈紙1锛夛紙a+b+c)(x-y)(2)(2a+b)^2 (3)=-2x(x+6y^2-4y^3)(4)x^(2n+1)(1+x^4)绗簩棰(1)(n+m)(n-m)(2)(y+2x)(y-2x)(3)(xy+1)(xy-1)(4)=8x^2-16y^2-7x^2-xy+xy =x^2-16y^2 =(x+4y)(x-4y)(5)=m^2-4 =(m+2)(m-2)(6)a^2(a+...
