在标准状况下，224mL某气体的质量为0.64g,求该气体的相对分子质量 在标准状况下，ag气体A与bg气体B的分子数相同，则与此有关...
\u9ad8\u4e00\u5316\u5b66\u9898 1.\u5728\u6807\u51c6\u72b6\u51b5\u4e0b\uff0c224ml\u67d0\u6c14\u4f53\u7684\u8d28\u91cf\u4e3a0.64g\uff0c\u5219\u8be5\u6c14\u4f53\u7684\u6469\u5c14\u8d28\u91cf\u4e3a\uff1f 2.\u914d\u5236\u6807\u51b5\u4e0b\u4f53\u79ef224ml\u53730.224L\u53730.01mol,0.64g/0.01mol,\u6240\u4ee5\u6807\u51b5\u4e0b\u6b64\u6c14\u4f53\u6469\u5c14\u91cf\u4e3a64g/mol,
A\u3001\u7531n=mM\u53ef\u77e5\uff0c\u5206\u5b50\u6570\u76f8\u540c\u7684\u6c14\u4f53\uff0c\u7269\u8d28\u7684\u91cf\u76f8\u540c\uff0c\u6469\u5c14\u8d28\u91cf\u4e4b\u6bd4\u7b49\u4e8e\u8d28\u91cf\u4e4b\u6bd4\uff0c\u5373A\u4e0eB\u6469\u5c14\u8d28\u91cf\u4e4b\u6bd4\u4e3aag\uff1abg=a\uff1ab\uff0c\u6545A\u6b63\u786e\uff1bB\u3001\u76f8\u540c\u72b6\u51b5\u4e0b\uff0c\u540c\u4f53\u79ef\u7684A\u4e0eB\u7684\u7269\u8d28\u7684\u91cf\u76f8\u540c\uff0c\u5219\u8d28\u91cf\u4e4b\u6bd4\u7b49\u4e8e\u6469\u5c14\u8d28\u91cf\u4e4b\u6bd4\uff0c\u5373\u4e3aa\uff1ab\uff0c\u6545B\u6b63\u786e\uff1bC\u3001A\u4e0eB\u76f8\u5bf9\u5206\u5b50\u8d28\u91cf\u4e4b\u6bd4\u4e3aa\uff1ab\uff0c\u540c\u8d28\u91cf\u65f6\u7531n=mM\u53ef\u77e5\uff0c\u5206\u5b50\u6570\u4e4b\u6bd4\u7b49\u4e8e1a\uff1a1b=b\uff1aa\uff0c\u6545C\u6b63\u786e\uff1bD\u3001\u6807\u51c6\u72b6\u51b5\u4e0b\uff0cVm\u76f8\u540c\uff0c\u7531\u03c1=mV\u53ef\u77e5\uff0c\u5bc6\u5ea6\u4e4b\u6bd4\u7b49\u4e8e\u6469\u5c14\u8d28\u91cf\u4e4b\u6bd4\u7b49\u4e8e\uff0c\u5373\u4e3aa\uff1ab\uff0c\u6545D\u4e0d\u6b63\u786e\uff1b\u6545\u9009D\uff0e
相对分子质量是纯数字（没有单位），它的值等于摩尔质量，摩尔质量=质量/摩尔数，题中直接给了质量，所以要求出摩尔数就可以了。标准状态下一摩尔任何气体的体积都是22.4L ，所以224mL气体的摩尔数为 0.224/22.4=0.01mol 。如此可以求出摩尔质量=0.64/0.01=64，所以该气体相对分子质量为64
在标准状况下224mL某气体的物质的量为0.01mol
该气体的摩尔质量M=0.64/0.01=64g/mol
该气体的相对分子质量为64
标准状况下，224ml是0.01mol，分子量=质量/物质的量=0.64/0.01=64g/mol
绛旓細鍡紝鏀硅繃鏉ヤ簡 锛1锛塶(HCl) = 224/22.4 = 10mol m(HCl) = 10*36.5 = 365g 鎵浠ョ洂閰哥殑璐ㄩ噺鍒嗘暟 = 365/(365+635) = 36.5 婧舵恫浣撶Н = (365+635)/1.2 = 833mL = 0.833L 鎵浠ョ洂閰哥殑鐗╄川鐨勯噺娴撳害 = 10/0.833 = 12mol/L 锛2锛夌█閲婂嶆暟 = 2/0.01 = 200 鎵浠ョ█閲婂悗鐗╄川鐨...
绛旓細锛1锛224L姘寲姘姘斾綋鐗╄川鐨勯噺涓224L22.4L/mol=10mol锛屾晠HCl鐨勮川閲=10mL脳36.5g/mol=365g锛屾按鐨勮川閲忎负635mL脳1g/mL=635g锛岃婧舵恫璐ㄩ噺鍒嗘暟涓365g365g+635g脳100%=36.5%锛岀瓟锛氳鐩愰吀涓憾璐ㄧ殑璐ㄩ噺鍒嗘暟鏄36.5%锛涳紙2锛夎鐩愰吀鐨勭墿璐ㄧ殑閲忔祿搴︿负1000脳1.18脳36.5%36.5mol/L=11.8mol/L锛屼护...
绛旓細鍥犱负鍓嶅悗鐨勪綋绉彲鑳芥湁鍙樺寲锛屾墍浠ヤ笉鑳界洿鎺ョ敤 224/22.4/0.33= 30.3mol/L 棰樻剰鍙煡锛22.4L姘ㄦ皵鐨勭墿璐ㄧ殑閲忎负 10mol 璐ㄩ噺涓10x17=170g锛0.33L姘寸殑璐ㄩ噺涓330g 婧舵恫鐨勮川閲忎负 170+330=500g 鎵浠ユ憾娑茬殑浣撶Н涓簃/p=500/0.8= 625ml=0.625L 鎵浠ョ墿璐ㄧ殑閲忔祿搴︿负 10/0.625=16mol/L 鎵浠ワ紝锛1...
绛旓細瑙ｏ細 鎵浠ワ紝A鐨勫垎瀛愬紡涓篊 3 H 6 瀹冨彲鑳界殑缁撴瀯绠寮忔槸锛欳H 3 CH锛滳H 2 銆
绛旓細瑙ｏ細锛1锛224L鐨勬隘鍖栨阿姘斾綋鐨勭墿璐ㄧ殑閲忎负锛歯(HCl) = V / Vm = 224 / 22.4 = 10mol 鍒欙紝姘寲姘㈢殑璐ㄩ噺涓猴細m(HCl) = n * M = 10 * 36.5 = 365g 閰嶅埗鎴愮殑姘寲姘㈡憾娑茬殑鎬昏川閲忔槸锛歮(婧舵恫) = m(HCl) + m(姘) = 365 + 635*1 = 1000g 鎵浠ワ紝鐩愰吀鐨勮川閲忓垎鏁版槸锛歸(HCl) =...
绛旓細瑙ｏ細鐢变簬婧舵恫鐨勮川閲忕瓑浜庢憾璐ㄥ姞婧跺墏锛岃孒Cl鏈224/22.4=10mol锛屸埓m锛圚Cl锛=n锛圚Cl锛壜稭锛圚Cl锛=10路36.5=365g锛宮锛圚20锛=635g锛堟按鐨勫瘑搴︽槸1g/cm3锛夆埓鐩愰厤璐ㄩ噺m涓簃锛圚Cl锛+m锛圚20锛=1000g锛屽叾涓璈Cl鐨勮川閲忓垎鏁颁负36.5%銆傝10mL鐩愰吀鐨勮川閲忎负1.18脳10=11.8g锛屽叾涓惈HCl11.8g脳36.5%=4....
绛旓細c锛堢█锛=11.8mol?L-1脳0.1L梅1.18L=1mol?L-1锛岀瓟锛氭墍寰楃█鐩愰吀鐨勭墿璐ㄧ殑閲忔祿搴︿负1mol?L-1锛涳紙3锛塶锛圢a2CO3锛=0.040L脳0.065mol?L-1=0.0026 mol锛屼娇鍙嶅簲涓嶄骇鐢烠O2姘斾綋锛鍙戠敓鍙嶅簲锛歂a2CO3+HCl鈺怤aHCO3+NaCl锛屾牴鎹柟绋嬪紡鍙煡娑堣桯Cl涓0.0026mol锛岃鍔犲叆绋鐩愰吀鐨勪綋绉渶澶氫笉瓒呰繃x mL锛...
绛旓細姘斾綋婧惰В鍚庯紝娑蹭綋鐨勪綋绉細鏈夊彉鍖栵紝浣嗘槸鎬昏川閲忕瓑浜庢憾璐ㄥ拰婧跺墏鐨勮川閲忓拰 m鎬=m(HCI)+m(H2O)=224L*36.5g/mol/22.4mol/L+635ml*1g/ml=646.63g V鎬=646.63g/1.18g/cm3=547.99cm3 c(鍒滺CI)=224L/22.4mol/L/0.54799L=18.25mol/L 0.010L*18.25mol/L=1.45L*c c=0.126mol/L ...
绛旓細HCl鐨勭墿璐ㄧ殑閲 224/22.4=10(mol)HCl鐨勮川閲10*36.5锛365锛坓锛夋憾娑茬殑璐ㄩ噺365+635*1锛1000锛坓锛塇Cl鐨勮川閲忓垎鏁365/1000脳100锛咃紳36.5锛 c锛圚Cl锛夛紳1000*1.19*36.5%/36.5=11.9(mo/L)绋閲婂悗娴撳害 11.9*10锛1190c 锛宑锛0.1锛坢ol/L锛
绛旓細锛1锛224L姘寲姘姘斾綋鐗╄川鐨勯噺涓224L22.4L/mol=10mol锛岀瓟锛氭墍寰楃洂閰镐腑婧惰川鐗╄川鐨勯噺鏄10mol锛涳紙1锛夋晠HCl鐨勮川閲=10mL脳36.5g/mol=365g锛屾按鐨勮川閲忎负635mL脳1g/mL=635g锛岃婧舵恫璐ㄩ噺鍒嗘暟涓365g365g+635g脳100%=36.5%锛岀瓟锛氳鐩愰吀涓憾璐ㄧ殑璐ㄩ噺鍒嗘暟鏄36.5%锛涳紙3锛夎鐩愰吀鐨勭墿璐ㄧ殑閲忔祿搴︿负1000...
