求由曲线y=lnx与直线y=lna及y=lnb所围图形的面积(b＞a＞0)．
【答案】：该图形为近似直角梯形,用积分的方法求解将梯形用平行于x轴的直线无限分割,得到无限多的近似小长方形,长为e^y,宽为dy,小长方形的面积为dS=e^y*dy,积分结果为S=e^y
对y从lna到lnb进行积分,得到的就是近似梯形的面积S = b-a
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