已知乙烯能发生以下转化关系：试回答下列问题：（1）写出②、④反应的化学方程式及反应类型：②
\u6025\u6c42:\u4e19\u70ef\u3001\u4e59\u70ef\u7684\u4e00\u4e9b\u53cd\u5e94\u5316\u5b66\u65b9\u7a0b\u5f0f\u548c\u53cd\u5e94\u7c7b\u578b.\u6025!!\u4e00
(1)CH3CH=CH2+Br2==CH3CHBr-CH3
(2)CH3CH=CH2+4O2==3CO2+2H2O
(3)CH3CH=CH2==CH3(CH-CH2)n \u6761\u4ef6\u4e3a\u50ac\u5316\u5242\uff0c\u9ad8\u6e29\u9ad8\u538b\u3002
(4)CH2=CH2+Br2==CH2BrCH3\u6216\u8005\u751f\u6210CH3CH2Br
(5)CH2=CH2+H2O==CH2CH2OH(\u4e59\u9187)
\u4e8c
\u751f\u6210\u7684\u767d\u8272\u6c89\u6dc0\u662fCACO3,100g1mol
CO2+CA(OH)2=CACO3
\u6bcf1molCO2\u751f1molCACO3,\u6545\u6709CO21mol,\u56e0\u800c\u6709 C\u539f\u5b50 1mol
\u7531\u6b64,1mol\u8be5\u70c3\u4e2d\u6709C 1mol/(0.5mol)=2mol
\u5e72\u71e5\u7ba1\u589e\u91cd\u662f\u7531\u4e8e\u5438\u6536\u4e86\u6c34\u548cCO2
2 Na2O2 + 2CO2 = 2Na2CO3 + O2
\u6bcf1molCO2\u589e\u91cd28g(\u653e\u51faO2\u540e\u5373\u76f8\u5f53\u4e8e\u5438\u6536\u4e86CO\uff09
\u56e0\u6709CO2 1mol\uff0c\u6545\u6709\u589e\u91cd28g
2 Na2O2 + 2H2O = 4NaOH+O2
\u6240\u4ee530g \u7684\u589e\u91cd\u4e2d\uff0c\u670928g\u56e0CO2\uff0c\u53e62g\u56e0\u6c34
\u6bcf1mol\u6c34\u589e\u91cd2g\uff08\u540c\u6837\u7684\u653e\u51fa\u6c27\u6c14\u540e\u5373\u76f8\u5f53\u4e8e\u5438\u6536\u7684\u662fH2\uff09\u6545\u4ea7\u7269\u4e2d\u67091mol\u7684\u6c34,\u6709H\u539f\u5b502mol
\u7531\u6b64,1mol\u8be5\u70c3\u4e2d\u6709H\u539f\u5b502/(0.5)=4mol
\u6545\u8be5\u70c3\u4e3aC2H4\u662f\u4e59\u70ef CH2=CH2
\u4e09\uff0cC6H12 \u540d\u4e3a \u5df1\u70ef
(\u8fd9\u91cc\u5316\u5b66\u7b26\u53f7\u4e0d\u597d\u6253\u554a,\u5e0c\u671b\u4f60\u80fd\u770b\u61c2)
CH2=CH2 + Br2 = BrCH2-CH2Br
CH2=CH2 + H2O = CH3-CH2OH
n CH2=CH2 = -(CH2-CH2)-n
\u5176\u4e2d\u540e\u9762\u7684n\u662f\u5c0f\u6ce8\uff0c \u5728\u6a2a\u7ebf\u7684\u4e0b\u65b9
（1）②反应②是乙醇在Cu或Ag作催化剂条件下发生氧化反应CH3CHO，反应方程式为，
故答案为：2C2H5OH+O2
| Cu/Ag |
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