求y=sin平方2x的导数 请问y=sin ²2x 如何求导数
\u6c42\u51fd\u6570y\uff1dsin²2x\u7684\u5bfc\u6570y\uff1dsin²2x\uff0c\u5373\uff1a
v=2x
u=sinv
y=u²
\u2234y'=2u\u00b7u'\u00b7v'
=2sinv\u00b7cosv\u00b72
=2sin(2x)cos(2x)\u00b72
=2sin(4x)
\u5982\u56fe\u6240\u793a\uff0c\u6ee1\u610f\u8bf7\u91c7\u7eb3
我的回答:
y=sin²2x
1. y' =2×(cos2x)×2sin2x
=4cos2x·sin2x
=2sin4x
2. y'' =2×(cos4x)×4
=8cos4x
y=sin²2x
y′=2×(cos2x)×2sin2x
=4cos2x·sin2x
=2sin4x
y〃=2(4x)′cos4x
= 8cos4x
绛旓細y=(sin2x)^2 y'=2(sin2x).(sin2x)'=2(sin2x).(cos2x).(2x)'=2(sin2x).(cos2x).(2)=4(sin2x).(cos2x)
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